(a) The average speed must you have for the second half of the trip to meet your goal is 8 km/h.
(b) The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.
<h3>
What is average velocity?</h3>
Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.
average velocity = total distance / total time
v = (d)/(0.5d/v₁ + 0.5d/v₂)
where;
- v is the average velocity
- v₁ is the average velocity during the first half
- v₂ is the average velocity during the second half
90 km/h = (d) / (0.5d/48 + 0.5d/v₂)
90(0.5d/48 + 0.5d/v₂) = d
0.9375d + 0.5d/v₂ = d
d(0.9375 + 0.5/v₂) = d
0.9375 + 0.5/v₂ = 1
0.5/v₂ = 0.0625
v₂ = 0.5/0.0625
v₂ = 8 km/h
Thus, the average speed must you have for the second half of the trip to meet your goal is 8 km/h.
The value obtained (8 km/h) is not reasonable for the second half of the distance since the first half is 48km/h.
Learn more about average velocity here: brainly.com/question/24739297
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Eight and I don’t know what else to say but for sure 8
Answer:
Explanation:
The magnitude of the acceleration makes an angle of 30° with the tangential velocity.
Resolving the acceleration to tangential and radial acceleration
at = aCos30 = √3a/2
ar = aSin30 = ½a
a = 2•ar
Then, the tangential acceleration is the linear acceleration, so the relationship between the tangential acceleration and angular acceleration is given as:
at = Rα
Then, α = at/R
since at = √3a/2
Then, α = √3 at/2R, equation 1
The radial acceleration is given as
ar = ω²R
Note that, at² + ar² = a²
at = √(a²-ar²)
Back to equation 1
α = √3 at/2R
α = √3√(a²-ar²)/2R
α = √3√(a²-(w²R)²)/2R
α = √3(a²-w⁴R²) / 2R
Also, a = 2•ar = 2w²R
Then,
α = √3((2w²R)²-w⁴R²) / 2R
α = √3(4w⁴R²-w⁴R²) / 2R
α = √3(3w⁴R²) / 2R
α = √9w⁴R² / 2R
α = 3w²R / 2R
α = 3w²/2
Initial velicity Vo.
Sin(23) = 24.7 / Vo
Vo = 24.7/Sin(23)
V0 = 63.2 m/sec
