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Rufina [12.5K]
4 years ago
10

Which statement best describes a risk associated with using radioisotopes in nuclear reactors? A Radioisotopes are very expensiv

e and do not produce the amount of energy that coal and oil produce. B If the radiation were to leak out of the reactors, it could produce an abundance of new plants and organisms. C Radioisotopes are extremely difficult to obtain and can only be retrieved from the Sun. D If the radiation were to leak out of the reactors, it could cause significant damage to living organisms.
Physics
1 answer:
monitta4 years ago
6 0
The correct answer is:
D If the radiation were to leak out of the reactors, it could cause significant damage to living organisms.

In fact, ionizing radiation that leaks out from nuclear reactor is able to damage the DNA of living organisms, causing mutations and/or diseases like cancer. 
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Explain Newtons Laws​
Vsevolod [243]

1) <u>Newton</u><u> </u> <u>first</u><u> </u> <u>law</u><u> </u><u>of</u><u> </u><u>motion</u>: state“If a body is at rest it reamain at rest and if it is in a motion it continu its motion unless a net external force acting on it”

This law also called <u>law</u><u> </u><u>of</u><u> </u><u>inertia</u><u> </u><u> </u>

2)<u> </u><u>Newton</u><u> </u><u>second</u><u> </u><u>law</u><u> </u><u>of</u><u> </u><u>motion</u><u>:</u><u> </u>states that ‟acceleration to the force acting on the body and inversky proportional to the <u>mass</u><u> </u> of the body”

3)<u> </u><u>Newton's third law of motion</u><u>:</u> It is not possible to exert a force abody with out the body exerting a forces in the opposite direction.

These forces are called <u>action</u><u> </u> and <u>reaction</u><u> </u> forces

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

8 0
3 years ago
A projectile is fired upward with an initial speed vo on an airless world. A short time later, it comes back down and has a fina
Zinaida [17]

Answer:

W_{grav} < 0

Explanation:

When a projectile is fired upwards with some initial speed then the it reaches the top of the projectile and then falls back to the ground.

According to the question we need to find the work done by the gravity which is acting downwards for the projectile when it is at a position just about to hit the ground in course of falling down.

As we know that work is given as:

W=F.s\cos\theta

here:

F= force of gravity on the object (which is acting downwards)

s= displacement of the object

  • Here the work done by the gravity at an instant just before the projectile hits the earth will be negative as the displacement is in the direction opposite to the force of gravity.
7 0
4 years ago
Two parallel plates are a distance apart with a potential difference between them. A point charge moves from the negatively char
IgorC [24]

Answer:

K' = 1200 J

Explanation:

To find the kinetic energy you first take into account the formula for the kinetic energy of the charge:

K=\frac{1}{2}mv^2 = 800J   (1)

m: mass of the charge

v: final speed of the charge when it reaches the positively charged plate.

Furthermore, you have that the acceleration of the charge is obtained by using the second Newton law:

F=ma=qE\\\\a=\frac{qE}{m} (2)

a: acceleration

E: electric field

q: charge

The electric field between two parallel plates is V/d, being V the potential difference and d the separation between plates. You replace E in (2) and obtain:

a=\frac{qV}{md}

Next, you take into account the following formula for the calculation of the final speed of the charge:

v^2=v_o^2+2ad\\\\v_o=0m/s\\\\v=\sqrt{\frac{2qVd}{md}}=\sqrt{\frac{2qV}{m}}

Next, you replace this value of v in (1):

K=\frac{1}{2}mv^2=\frac{1}{2}m(\frac{2qV}{m})=qV = 880J   (3)

If the distance between plates is tripled, and the potential difference is halved, you have for the new final speed:

v'^2=v'_o^2+2a(3d)\\\\v_o=0m/s\\\\v'=\sqrt{6ad}=\sqrt{6(\frac{q}{md})\frac{V}{2}d}=\sqrt{\frac{3qV}{m}}

And the kinetic energy becomes:

K'=\frac{1}{2}mv^2=\frac{1}{2}m(\frac{3qV}{m})=\frac{3}{2}qV    (4)

You calculate the ratio between both kinetic energies K and K', that is, you divide equations (3) and (4), in order to find the new kinetic energy:

K=qV=800J\\\\K'=\frac{3}{2}qV\\\\\frac{K}{K'}=\frac{qV}{3/2\ qV}=\frac{2}{3}\\\\K'=\frac{3}{2}K=\frac{3}{2}(800J)=1200J

hence, the kinetic energy of the charge incresases to 1200J

4 0
3 years ago
A(n) ________ describes the shape of a planet’s orbital path. astronomical unit
sleet_krkn [62]
It is an ellipse. 

Hope this helps!
8 0
3 years ago
Read 2 more answers
In a police ballistics test, 2.00-g bullet traveling at 700 m/s suddenly hits and becomes embedded in a stationary 5.00-kg wood
aksik [14]

Answer:

  • Here we use the conservation of momentum theorem.

  • m stands for mass, and v stands for velocity. The numbers refer to the respective objects.

  • m1v1 + m2v2 = m1vf1 + m2vf2

  • Since the equation is perfectly inelastic, the final velocity of both masses is the same. Let’s account for this in our formula.

  • m1v1 + m2v2 = vf(m1 + m2)

<u>Let’s substitute in our givens.</u>

(0.002 kg)(700 m/s) + (5 kg)(0 m/s) = vf(0.002 kg + 5 kg)

I assume you are proficient in algebra I, so I will not include the steps to simplify this equation.

Note that I have considered the bullet’s velocity to be in the positive direction,

The answer is vf = 0.280 m/s

3 0
3 years ago
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