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True [87]
3 years ago
14

the loudness of a person's voice depends on the A. force with which air rushes across the vocal folds B. strength of the intrins

ic laryngeal muscles C. length of the vocal folds D. thickness of vestibular folds
Physics
1 answer:
blsea [12.9K]3 years ago
5 0

Answer: A. force with which air rushes across the vocal folds

Explanation:

The human voice is produced in the larynx, whose essential part is the glottis. This is how the air coming from the lungs is forced during expiration through the glottis, making its two pairs of vocal folds to vibrate.

It should be noted that this process can be consciously controlled by the person who speaks (or sings), since the variation in the intensity of the sound of the voice depends on the strength of the breath.

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A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km.(a) What is the gravitational acceler
Pepsi [2]

Answer:

331665750000\ m/s^2

3257806.62409 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Sun = 1.989\times 10^{30}\ kg

r = Radius of Star = 20 km

u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2

The gravitational acceleration at the surface of such a star is 331665750000\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s

The velocity of the object would be 3257806.62409 m/s

8 0
3 years ago
An acceleration constraint says that in some circumstances An acceleration constraint says that in some circumstances the accele
Pavel [41]

Answer:

two objects must have accelerations of equal magnitude.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

a = \frac{v  -  u}{t}

Where,

a is acceleration measured in ms^{-2}

v and u is final and initial velocity respectively, measured in ms^{-1}

t is time measured in seconds.

Acceleration constraint refers to a precise relationship between the acceleration of two physical objects.

An acceleration constraint says that in some circumstances two objects must have accelerations of equal magnitude.

4 0
3 years ago
If gravity did not affect the path of a horizontally thrown ball the ball would ____
Setler79 [48]
If gravity did not affect the path of a horizontally thrown ball the ball would eventually slow due to air resistance. If the ball were somehow thrown in a vacuum devoid of gravity and air, it would technically continue in a straight line forever. 

5 0
3 years ago
If a 90 kg hockey player slows from 18 m/s to 12 m/s over 0.6 s, what is the force exerted by his skates on the ice? A. -540 N B
Zielflug [23.3K]

Answer:

B. -900 kg-m/s2

Explanation:

First of all, we need to calculate the acceleration of the hockey player, which is given by:

a=\frac{v-u}{t}

where

v = 12 m/s is the final speed

u = 18 m/s is the initial speed

t = 0.6 s is the time

Substituting into the formula, we find

a=\frac{12 m/s-18 m/s}{0.6 s}=-10 m/s^2

And now we can calculate the force exerted by using Newton's second law:

F=ma

where m=90 kg is the mass of the hockey player. Substituting into the formula, we find

F=(90 kg)(-10 m/s^2)=-900 N

5 0
3 years ago
A 2 kg ice cube is released from point A and slides on a frictionless track as shown in the figure. Determine the speed of the c
kherson [118]

According to the conservation of energy

  • Potential energy at any given instance is equal to the Kinetic energy as energy can neither be created nor be destroyed

Mass is 2kg=m

#A

h=5m

  • PE=mgh

PE

  • 2(9.8)(5)
  • 10(9.8)
  • 98J

Now

  • KE=98J
  • 1/2mv²=98J
  • 1/2×2v²=98J
  • v²=98J
  • v=√98
  • v=9.4m/s

#B

h=3.2m

PE:-

  • 2(3.2)(9.8)
  • 6.4(9.8)
  • 62.7J

Now

  • KE=62.7J
  • 1/2mv²=62.7
  • v²=62.7
  • v=√62.7
  • v=7.9m/s

#C

h=2m

PE

  • 2(2)(9.8)
  • 4(9.8)
  • 39.2J

Now

  • v²=39.2
  • v=√39.2
  • v=6.3m/s
8 0
2 years ago
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