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Alik [6]
3 years ago
15

Consider the following statements a. The centripetal acceleration might better be expressed as-T(t) because it is a vector b. Th

e magnitude of the centripetal acceleration is vadial/R acceleration iS U acceleration iS U tangential d. A particle that is going along a path with local radius of curvature R at speed s experiences a centripetal acceleration-s/R. e. If you are in a car turning left, the force you feel pushing you to the right is the force that causes the centripetal acceleration. In these statements Uradial refers to the component of the velocity of an object in the direction toward or away from the origin of the coordinate system or the rotation axis. Conversely, Vtangential refers to the component of the velocity perpendicular to Vradial Identify the statement or statements that are false 1.a only2. b only 3.c only 4.d only 5.e only 6.b and e 7.c and e 8.d and e
Physics
1 answer:
ruslelena [56]3 years ago
5 0

Answer:

8. d and e

Explanation:

Centripetal acceleration a= V^2/R where v is the speed of tangential to the Radius of curvature R and centripetal force is the force toward the center of the circle.  

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Which event took place during the Copernican revolution, when most people started to believe in a heliocentric model of the sola
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In a real system of levers, wheels, or pulleys, the AMA is less than the IMA because _____.
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In a real system of levers, wheel or pulleys, the AMA (actual mechanical advantage) is less than the IMA (ideal mechanical advantage) because of the presence of friction.

In fact, the IMA and the AMA of a machine are defined as the ratio between the output force (the load) and the input force (the effort):
IMA= \frac{F_{out}}{F_{in}}
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In March 2006, two small satellites were discovered orbiting Pluto, one at a distance of 48,000 km and the other at 64,000 km. P
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Answer

given,

distance of first satellite = 48,000 Km

distance of second satellite = 64,000 Km

orbital period = 6.39 day

Using equation of time period

  T = \dfrac{2\pi r^{3/2}}{\sqrt{Gm_{pluto}}}

now, from the above equation we can say that only variable is Time period and r is the radii of orbit.

from the first satellite

   \dfrac{T_{charon}}{r^{3/2}_{charon}}=\dfrac{T_{sat1}}{r^{3/2}_{sat1}}

   T_{sat1}=\dfrac{T_{charon}\ r^{3/2}}{r^{3/2}_{charon}}

   T_{sat1}=\dfrac{6.39\times (48000)^{3/2}}{19600^{3/2}}

   T_{sat1}=24.5\ days

for second satellite

   T_{sat2}=\dfrac{T_{charon}\ r^{3/2}_{sat2}}{r^{3/2}_{charon}}

   T_{sat1}=\dfrac{6.39\times (64000)^{3/2}}{19600^{3/2}}

   T_{sat1}=37.7\ days

7 0
3 years ago
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