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vladimir1956 [14]
2 years ago
6

Charge q is 1 unit of distance away from the source charge S. Charge p is four times further away. The force exerted between S a

nd q is _____ the force exerted between S and p.
one0fourth
four times
one0sixteenth
sixteen times
Physics
2 answers:
velikii [3]2 years ago
7 0
The correct answer for the question that is being presented above is this one: "one0fourth." Charge q is 1 unit of distance away from the source charge S. Charge p is four times further away. The force exerted between S and q is one0fourth the force
zhenek [66]2 years ago
4 0

The correct answer is:

sixteen times


In fact, the distance between charge q and the source S is 1 unit. Instead, the distance between charge p and the source S is 4 units. The magnitude of the electrostatic force is inversely proportional to the square of the distance between the charge and the source:

E \sim \frac{1}{r^2}

where r is the distance. If we take the force between q and S as reference, we have r=1, so that

E_{qS}=\frac{1}{1^2}=1

while the force between p and S is

E_{pS}=\frac{1}{4^2}=\frac{1}{16}

Therefore, we see that the force exerted between q and S is 16 times the force exerted between p and S.

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Which phenomenon occurs when the moon and Earth are aligned with the sun? A. Retrograde motion B. Solstice C. Equinox D. Eclipse
muminat

Answer: Eclipse

Explanation: A lunar eclipse occurs when the full moon moves through the shadow of the Earth. This can only happen when the Earth is between the Moon and the Sun and all three are lined up in the same plane, called the ecliptic. The ecliptic is the plane of Earth's orbit around the Sun.

7 0
3 years ago
A4 kg bowling ball begins rolling down a at bowling alloy at 6 m/s . When it strikes the pins, it is estimated to be moving at 5
Paul [167]

Answer:

Energy lost due to friction is 22 J      

Explanation:

Mass of the ball m = 4 kg

Initially velocity of ball v = 6 m/sec

So kinetic energy of the ball KE=\frac{1}{2}mv^2

KE=\frac{1}{2}\times 4\times 6^2=72J

Now due to friction velocity decreases to 5 m/sec

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KE=\frac{1}{2}\times 4\times 5^2=50J

Therefore energy lost due to friction = 72 -50 = 22 J

8 0
3 years ago
A can of sardines is made to move along an x axis from x = 0.47 m to x = 1.20 m by a force with a magnitude given by F = exp(–8x
sattari [20]
If the force were constant or increasing, we could guess that the speed of the sardines is increasing. Since the force is decreasing but staying in contact with the can, we know that the can is slowing down, so there must be friction involved.
Work is the integral of (force x distance) over the distance, which is just the area under the distance/force graph.
The integral of exp(-8x) dx that we need is (-1/8)exp(-8x) evaluated from 0.47 to 1.20 .

I get 0.00291 of a Joule ... seems like a very suspicious solution, but for an exponential integral at a cost of 5 measly points, what can you expect. On the other hand, it's not really too unreasonable. The force is only 0.023 Newton at the beginning, and 0.000067 newton at the end, and the distance is only about 0.7 meter, so there certainly isn't a lot of work going on. The main question we're left with after all of this is: Why sardines ? ?
6 0
2 years ago
Can anybody write a short poem about friction
Luden [163]
Answer:

you will be the clouds
and I will be the sky.
you will be the ocean
and I will be the shore.
you will be the trees
and I will be the wind.

whatever we are, you and I will always collide.

There you go! Let me know if it helped.
:)
8 0
2 years ago
An electron is emmited by an atomic nucleus in the process of...
Sliva [168]
I’m pretty sure it’s Radioactive decay
8 0
3 years ago
Read 2 more answers
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