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vladimir1956 [14]
3 years ago
6

Charge q is 1 unit of distance away from the source charge S. Charge p is four times further away. The force exerted between S a

nd q is _____ the force exerted between S and p.
one0fourth
four times
one0sixteenth
sixteen times
Physics
2 answers:
velikii [3]3 years ago
7 0
The correct answer for the question that is being presented above is this one: "one0fourth." Charge q is 1 unit of distance away from the source charge S. Charge p is four times further away. The force exerted between S and q is one0fourth the force
zhenek [66]3 years ago
4 0

The correct answer is:

sixteen times


In fact, the distance between charge q and the source S is 1 unit. Instead, the distance between charge p and the source S is 4 units. The magnitude of the electrostatic force is inversely proportional to the square of the distance between the charge and the source:

E \sim \frac{1}{r^2}

where r is the distance. If we take the force between q and S as reference, we have r=1, so that

E_{qS}=\frac{1}{1^2}=1

while the force between p and S is

E_{pS}=\frac{1}{4^2}=\frac{1}{16}

Therefore, we see that the force exerted between q and S is 16 times the force exerted between p and S.

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