All categories

3 years ago

Can someone give me the answers asap! 15 points

Mathematics

1 answer:

Eduardwww [97]3 years ago

3 0

In the first question,
Since D is the midpoint of line segment AC.
therefore, AD=DC.

In triangles, ABD & CBD.
Since, AB is congruent to CB and BD is a common side between those two triangles.
Therefore, AD is congruent to DC.

Finally, in triangles DEA & DEC
Since, ED line segment is a common side between those triangles and the measure of angle EDA is as the same of angle EDC which are equal to 90 degrees and AD is congruent to DC.
Therefore, triangle EDA is congruent to triangle EDC ( you have to take care of the triangle order letters in congruence) and EC is congruent to EA.

You might be interested in

The salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation o

andrey2020 [161]

Answer:

D. 54,900

Step-by-step explanation:

We have been given that the salary of teachers in a particular school district is normally distributed with a mean of $50,000 and a standard deviation of $2,500.

To solve our given problem, we need to find the sample score using z-score formula and normal distribution table.

First of all, we will find z-score corresponding to probability $0.975(1-0.025)$ using normal distribution table.

From normal distribution table, we get z-score corresponding is $1.96$ .

Now, we will use z-score formula to find sample score as:

$z=\frac{x-\mu}{\sigma}$ , where,

$z$ = Z-score,

$z$ = Sample score,

$\mu$ = Mean,

$\sigma$ = Standard deviation

$1.96=\frac{x-50,000}{2,500}$

$1.96*2,500=\frac{x-50,000}{2,500}*2,500$

$4900=x-50,000$

$4900+50,000=x-50,000+50,000$

$54900=x$

Therefore, the salary of $54900 divides the teachers into one group that gets a raise and one that doesn't.

4 0

3 years ago

One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R

marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

$Urn\ 1 = \{B_1, R_1, R_2, R_3\}$

$Urn\ 2 = \{R_4, R_5, B_2, B_3\}$

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

If urn 2 is selected, the following selection exists:

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

See attachment for possibility tree

Solving (b): The total number of outcome

For urn 1

There are 4 balls in urn 1

$n = \{B_1,R_1,R_2,R_3\}$

Each of the balls has 3 subsets. i.e.

$B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]$

So, the selection is:

$Urn\ 1 = 4 * 3$

$Urn\ 1 = 12$

For urn 2

There are 4 balls in urn 2

$n = \{B_2,B_3,R_4,R_5\}$

Each of the balls has 3 subsets. i.e.

$B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]$

So, the selection is:

$Urn\ 2 = 4 * 3$

$Urn\ 2 = 12$

Total number of outcomes is:

$Total = Urn\ 1 + Urn\ 2$

$Total = 12 + 12$

$Total = 24$

5 0

3 years ago

Please help me!!!! Super confused

valkas [14]

The correct answer to 38 is B

4 0

3 years ago

If you divide 30 by half and add ten, what do you get?

Pavlova-9 [17]

Answer:

Step-by-step explanation:

Dividing is multiplying by the reciprocal.

So 30 divided by 1/2

is like 30(2)=60

Then add 10 so 60+10=

5 0

3 years ago

Read 2 more answers

The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d

kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

P(x > x') = P(z > z') = 35% = 0.35

P(z > z') = 1 - P(z ≤ z') = 0.35

P(z ≤ z') = 1 - 0.35 = 0.65

Using the normal distribution table,

z' = 0.385

we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

0.385 = (x' - 560)/260

x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!

8 0

3 years ago