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velikii [3]
3 years ago
13

Find the product of (x^2y^2-5)^2

Mathematics
1 answer:
lukranit [14]3 years ago
3 0
Remember
(x^m)(x^n)=x^(m+n)

(x^2y^2-5)^2=
(x^2y^2-5)(x^2y^2-5)=
x^4y^4-5x^2y^2-5x^2y^2+25=
x^4y^4-10x^2y^2+25

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<u>Step-by-step explanation:</u>

A_{trapezoid} = \frac{b_{1}+b_{2}}{2}*h

                       = \frac{25+33}{2}*30

                       = \frac{58}{2}*30

                       = 29 * 30

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A_{circle} = \pi r^{2}

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                  = 16π

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Area of the park = A_{trapezoid} - A_{circle}

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= 819.73

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