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mrs_skeptik [129]
3 years ago
8

If i get a 98 on a test that is worth 25% of my grade what is my grade? (my grade right now is a 76) . 30 points !

Mathematics
1 answer:
kykrilka [37]3 years ago
4 0

Answer:

Not 100% sure but I think it's 94.62

Step-by-step explanation:

98*25%=24.5

76*24.5%=18.62

18.62+76=94.62

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75% because 9/12 simplified is 3/4 which is 75%
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I really need help I would appreciate it if someone could help me
sleet_krkn [62]

Answer:

a) The vertex of the graph is (h,k) = (0, 31), b) a = -16, c) The equation of the parabola is f(t) = -16\cdot t^{2}+31.

Step-by-step explanation:

a) The tennis ball experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from Earth's rotation and air viscocity are negligible. The height of the ball in time is represented by a second order polynomial. Hence, the vertex of the parabola is the initial point highlighted in graph.

The vertex of the graph is (h,k) = (0, 31).

b) If we know that (h,k) = (0, 31), f(t) = a\cdot (t-h)^{2} + k and (t,f(t)) = (1,15), then the value of a is:

f(t) = a\cdot (t-h)^{2} + k

15 = a\cdot (1-0)^{2}+31

15 = a\cdot 1 + 31

a = 15-31

a = -16

c) The equation of the parabola is f(t) = -16\cdot t^{2}+31.

4 0
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If morgan spends 23 on gas, what is the total distance the girls could travel
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Read 2 more answers
Solve question 3 for <br> 41 points
Sever21 [200]

Answer:

(2)

Step-by-step explanation:

Our logarithmic expression is: ln(\frac{\sqrt{e} }{y^3} ).

Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

ln(\frac{\sqrt{e} }{y^3} )=ln(\sqrt{e} )-ln(y^3)

Also, we can write square roots as powers of one-half, so √e = e^{1/2}. There's another log property that: ln(a^b)=b*ln(a). We can apply that here for both the √e and the y³:

ln(\sqrt{e} )-ln(y^3)=\frac{1}{2} ln(e)-3ln(y)

Finally, note that ln(e) is just 1, so we have:

\frac{1}{2} ln(e)-3ln(y)=\frac{1}{2} -3ln(y)=\frac{1-6ln(y)}{2}

The answer is thus (2).

<em>~ an aesthetics lover</em>

7 0
2 years ago
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