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kondaur [170]
2 years ago
11

Kate has $60. If shirts cost $18.99, estimate the maximum number of shirts she can buy by rounding the price to the nearest ten.

Mathematics
1 answer:
Molodets [167]2 years ago
7 0

Kate can get a max of 3 shirts.

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Rebecca bought candy boxes in the shape of a square pyramid to use for party favors. The side length of each box is 3.6 inches,
diamong [38]

Answer:

Yes maybe.

Step-by-step explanation:

Well basically if we find the volume of 20 pieces of candy in all, that would be= 20*0.8= 16 cu.inches

And then if we find the volume of the square based pyramid, that would certainly be= 3.6*3.6*4 that is 51.84

Then lastly, if we do, 51.84 ÷16 the final answer will be 3.24. Which might actually be the answer as the pieces of candy certainly can't pass the limit 20 according to me.

5 0
3 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

6 0
2 years ago
Plzzzzz help due in a few minutes and will fail if not answered by this plzzzzzz help can not figure out!!!!!!!! Will give brain
gulaghasi [49]
You want it to be 14 by 16 tiles to recreate King Kyle’s tomb.
6 0
3 years ago
Read 2 more answers
The two cones below have the same radius, height, and
lozanna [386]

Answer:

yes

Step-by-step explanation:

The cones are not concurrent because one cone is obliquewhich makes the length of these land height is different have the same radius same volumes and same height are the cones concurrent is the corresponding slant height sorry equal .concurrent counts must have concurrent corresponding slant height with all this corresponding being concurrent

3 0
1 year ago
A triangle has angles measuring 23 and 48 degrees. What is the measure of the third angle?
icang [17]

Answer:

109

Step-by-step explanation:

Hope this helped :)

6 0
2 years ago
Read 2 more answers
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