Answer: Mike's arm span is 7.165 cm longer than the George's one.
Step-by-step explanation:
We have that the association between height and arm span is modeled by the equation
y = 4.5 + 0.977*x
where y is height and x is arm span.
Mike is 172 cm tall, so his arm span is:
172cm = 4.5 + 0.977*x
x = (172 - 4.5)/0.977 = 171.443 cm
and George is 165 cm tall, so his arm span is:
x = (165 - 4.5)/0.977 = 164.278 cm
Then the difference between their arm span is:
171.443cm - 164.278cm = 7.165 cm
So Mike's arm span is 7.165 cm longer than the George's one.
Answer:
97.2
Step-by-step explanation:
hi I m from India nice to meet you bro
Data from random samples will not always include the same values. Values are chosen randomly and they may or may not be the same. So means will vary among samples.
=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
Answer: B. 31
Step-by-step explanation:
This linear regression was constructed by relating the hours practiced per week and the number of competitions won.
Going by this graph, the number of competitions they can expect to win at 5 practices a week is 31.
This is derived by looking for the point where 5 competitions on the x-axis intersects with the line. This point is at 31 competitions on the y axis which would make it the answer.
