Question

Calculate the volume of buffer to which 500mL of 60 mM potassium chloride solution must be diluted to make a new concentration of 0.001M.

Answer 1

Answer:

$30,000$ mL

Explanation:

Given -

Volume of buffer $= 500$ mL

Concentration of solution $= 60$ mM$= 0.06$M

New concentration of the solution $= 0.001$M

As we know

$C_1* V_1= C_2*V_2$

Where

$C_1, C_2$ are the concentration of the solution before and after dilution.

And $V_1, V_2$ are the volume of solution before and after dilution.

Substituting the given values in above equation, we get -

$500* 0.06 = V_2* 0.001\\V_2 = \frac{30}{0.001} \\V_2 = 30,000$mL