Answer:
<h2>
(f + g)(x)≥3 for all values of x</h2>
Step-by-step explanation:
Given the expressions f(x) = |x| + 9 and g(x) = –6, sine f(x) contains the absolute value of a variable x, this absolute value can be negative and positive. Therefore f(x) can be expressed in two forms as shown;
f(x) = x+9 and f(x) = -x+9
If f(x) = x+ 9 and g(x) = -6
(f + g)(x) = f(x)+ g(x)
(f + g)(x) = x+9+(-6)
(f + g)(x) = x+9-6
(f + g)(x) = x+3
Similarly, if f(x) = -x+ 9 and g(x) = -6
(f + g)(x) = f(x)+ g(x)
(f + g)(x) = -x+9+(-6)
(f + g)(x) = -x+9-6
(f + g)(x) = -x+3
(f + g)(x) = 3-x
In both expresson, we have bith x to be positive and negative, hence we can write the value of resulting x as an absolute value as shown;
(f + g)(x) = |x|+3
This shows that (f + g)(x)≥3 for all values of x
Answer:
x=8
Step-by-step explanation:
Answer:
what you're finding
Step-by-step explanation:
you fill it in for the f(n)
4+3(x+2)=-8
4+3x+6=-8
10+3x=-8
-10 -10
3x= -18
X= -6
Answer
Find out the total amount of interest earned at the end of 3 years .
To prove
Formula
As given
Dawnie deposited $350 In a savings account earns 3% simple interest over three years .
Here Principle = $350
Interest = 3%
Time = 3 years
Put in the above formula
Simple interest = $31.5
Therefore $31.5 is the total amount of the interest in 3 years.