1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ira Lisetskai [31]
3 years ago
11

What number is 73% of 215?

Mathematics
2 answers:
german3 years ago
8 0
The answer is (B). n=0.73 × 215
devlian [24]3 years ago
6 0
B is the right answer.
You might be interested in
PLEASE HELP ME SOLVE!
Crank

Answer:

F(-6) = <u>2*(-6) + 1</u>

            5*(-6) -2

= <u>-11  </u>

  -32

=   <u>11     </u>

      32

5 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP GEOMETRY 20 PTS REAL ANSWERS ONLY
kodGreya [7K]

Answer:

Step-by-step explanation:

Use the Law of Cosines to find the measure of angle A from the lengths of the sides.

A = arccos[(b²+c²-a²)/(2bc)] ≅ 29.9°

B = arccos[(a²+c²-b²)/(2ac)] ≅ 54.8°

C = 180 - A - B = 95.3°

7 0
2 years ago
Ryan deposited $6,700 into an account at the Town Bank, earning 3.4% interest compounded annually. He made no deposits or withdr
Nonamiya [84]

Answer: The amount of money in his account after 4 years = $7,658.73

Step-by-step explanation:

If interest is compounded annually, then formula to compute amount :

A=P(1+r)^n, where P+ principal value, r= rate of interest, n= time ( in years).

As per given,

P= $6700 ,  r = 3.4% =0.034, n =4

A=6700(1+0.034)^4\\\\=6700(1.034)^4\\\\=6700(1.14309455234)\approx7658.73

Hence, the amount of money in his account after 4 years = $7,658.73

6 0
3 years ago
A drug used to relieve anxiety and nervousness has a half-life of 16 hours. if a doctor prescribes one 2.8-milligram every 24 ho
dlinn [17]

After 24 hours, 35.4% of the initial dosage remains on the body.

<h3>What percentage of the last dosage remains?</h3>

The exponential decay is written as:

f(x) = A*e^{-k*x}

Where A is the initial value, in this case 2.8mg.

k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

k = ln(2)/16h

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

f(24h) = 2.8mg*e^{-24h*ln(2)/16h} = 0.9899 mg

The percentage of the initial dosage that remains is:

P = \frac{0.9899mg}{2.8mg}*100\% = 35.4\%

If you want to learn more about exponential decays:

brainly.com/question/11464095

#SPJ1

8 0
1 year ago
Six friends share cost of gift. They pay $90 and receive $42 in change. How much does each pay?
miskamm [114]
Lets look at the info we have:-

6 friends
Pay $90 and receive $42 in change.

Question:-

How much does each friend pay?

To answer this first we nee to find out how much they paed in total. lets do that 1st:-

90 - 42 = 48
They paid $48 for the gift.

CHECK OUR WORK:-

48 + 42 = 90
We were RIGHT!!

Now lets divide to find out how much each person paid:- 

48 ÷ 6 = 8
Each friend pays $8.

CHECK OUR WORK:-

8 × 6 =  48
We were RIGHT!!

So, each friend pays $8 for the gift.

Hope I helped ya!! xD
7 0
3 years ago
Read 2 more answers
Other questions:
  • Can you guys help please with all of the questions please
    11·1 answer
  • Need help with 2 and 3 and express I’m radical form
    8·1 answer
  • The diagram of the hexagon below displays all the lines of symmetry for the hexagon. True or false
    6·2 answers
  • How many ounces of a 12% alcohol solution and a 22% alcohol solution must be combined to obtain 80 ounces of a 17% solution?
    9·1 answer
  • We know 5. 3 = 15. Which 2 of the following statements must also be true? (You need to select 2 answers) 9 5 is a factor of 15.
    10·1 answer
  • (cosx - sinx)(secx + cscx) = cotx - tanx
    6·1 answer
  • 8 (n + 2) = __n + __
    13·2 answers
  • (-4) ( ? ) = -20 <br> please help
    9·2 answers
  • Find cos 0, where 0 is the angle shown.<br> Give an exact value, not a decimal approximation.
    10·1 answer
  • Please help ill mark brilliant​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!