What does the p mean in 1s22s22p63s??

A calorimeter was used to measure the heat change when an ionic compound dissolves in water. The final mass of the contents of t

Lemur [1.5K]

The answer
the main formula is given by
Q=mSDT
where m= mass
s= specific heat
DT= <span>change in temperature

so Q = 50.89 x 1.8x 4.11 = 376.48</span>

6 0

3 years ago

What is the mass of an object that has a density of 0.500 g/cm3 and a volume of 5.00 mL?

attashe74 [19]

Answer:

<h2>The answer is 2.5 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density = 0.5 g/cm³

1 mL = 1 cm³

5 mL = 5 cm³

volume = 5 cm³

The mass is

mass = 0.5 × 5

We have the final answer as

Hope this helps you

4 0

3 years ago

If we react 30 grams of ethane (C2H6 ) with 320 grams of oxygen, how many grams of carbon dioxide would we make

V125BC [204]

The mass of carbon dioxide that would be made by reacting 30 grams C2H6 with 320 grams O2 will be 80 grams

From the balanced equation of the reaction:

$2C_2H_6+7O_2---4CO_2+6H_2O$

The mole ratio of C2H6 to O2 is 2:7.

Mole of 30 grams C2H6 = mass/molar mass

= 30/30

= 1 mole

Mole of 320 grams O2 = 320/32

= 10 moles

Thus, C2H6 is the limiting reactant.

Mole ratio of C2H6 to CO2 according to the equation = 1:2

Since the mole of C2H6 is 1, the equivalent mole of CO2 would, therefore, be 2.

Mass of 2 moles CO2 = mole x molar mass

= 2 x 44

= 88 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults

6 0

2 years ago

A city's water supply is contaminated with a toxin at a concentration of 0.63 mg/L. For the water to be safe for drinking, the c

Shalnov [3]

Answer:

Approximately 22.37 days, will it take for the water to be safe to drink.

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

k is rate constant

Given that:- k = 0.27 (day)⁻¹

$[A_0]$ = 0.63 mg/L

$[A_t]=1.5\times 10^{-3}$ mg/L

Applying in the above equation as:-

$1.5\times 10^{-3}=0.63e^{-0.27\times t}$

$63e^{-0.27t}=150\times \:10^{-3}$

$e^{-0.27t}=\frac{1}{420}$

$t=\frac{100\ln \left(420\right)}{27}=22.37$

<u>Approximately 22.37 days, will it take for the water to be safe to drink.</u>

7 0

3 years ago

Give the numbers of significant figures indicated 60.1<br><br> 0 <br> 3 <br> 1 <br> 2

denpristay [2]

3 significant figures

4 0

2 years ago

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