Answer : The specific heat of tin is, 0.213 J/g.K
Explanation :
Formula used :
where,
q = amount of heat lost = -399.4 J
c = specific heat capacity of tin = ?
m = mass of tin = 25.0 g
= final temperature = 
= initial temperature = 
Now put all the given values in the above formula, we get:
Therefore, the specific heat of tin is, 0.213 J/g.K
Benedict's solution is used to test simple sugars, such as glucose. It is blue solution, when sugar is present, it turns to orange / brick red. Depends on the concentration of sugar.
Given:
1.50 L
62.5 grams
and the MM of MgO: 40.31 g/mol
Molarity: mol/L
First, find mol.
62.5 g x 1mole ÷ 40.31 g = 1.55 mol
then divide mol and the given liters
1.55mol ÷ 1.50 L= 1.03 M
Answer:
Real gas particles have significant volume
Real gas particles have more complex interactions than ideal gas particles.
Explanation:
An ideal gas is an imaginary concept and a gas behaves almost ideally at certain pressure and temperature conditions.
The gas in real deviates from the ideal behavior as some of the assumptions made for ideal gases are not true in case of real gases.
Real gas particles have significant volume as compared to vessel unlike ideal gases.
There are interactions present in between real gas molecules at high pressure conditions.
Answer:
The formula for the precipitate is PbI₂
Explanation:
The chemical reaction is:
Pb(NO₃)₂ (aq) + 2KI (aq) → 2KNO₃ (aq) + PbI₂ (s)↓
All the iodides, with these cations (Ag⁺, Pb²⁺, Cu⁺, Hg²⁺, Bi⁺³ and Sn⁺⁴) produce insolubles solid.
