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Aloiza [94]
3 years ago
13

During one month, there were 2,000 people who used the advertiser links on a website. The percent of people who clicked on each

Mathematics
1 answer:
erica [24]3 years ago
4 0

Answer:

500

Step-by-step explanation:

During one month, there were 2,000 people who used the advertiser links on a website. The percent of people who clicked on each

advertisement link is shown in the circle graph. Calculate the number of people who clicked on the link for each type of advertisement. How

many people used the Music link?

Advertiser Links

Computers

2396

Music

25%

TVS

3%

Movies

1796

Cell phones

32%

340

450

500

540

Then You Turn The Music Percent Into A Decimal Which Is .25% Then Times That By 2000 And You Get .25 X 2000 = 500

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Step by step explanation
vodka [1.7K]

Answer: x = 4 and y = -3

Step-by-step explanation:

2x + 4y = -4

2x = -4 - 4y

x = -2 - 2y

Now that we have solved the first equation for x, we plug (-2 - 2y) into the other equation in place of x and then solve for y.

3(-2 -2y) + 5y = -3

-6 - 6y + 5y = -3

-y = 3

y = -3

Now that we know y, we plug it into the original equation and solve for x.

2x + 4(-3) = -4

2x + -12 = -4

2x = 8

x = 4

You can check the answer by plugging both x and y into either of the original equations.

4 0
3 years ago
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow
prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

CI=\hat{Y}\pm t_{Critical}\times S_{e}

Where,

\hat{Y}= predicted value of lead content when traffic flow is 15.

\to df=n-1=8-1=7

 95\% \ CI\  is\  (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\

     =\frac{1059.8}{2}\\\\=529.9

Calculating thet-critical valuet_{ \{\frac{\alpha}{2},\ df \}}=-2.365

The lower predicted value =529.9-2.365(Se)

463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076

When 99\% of CI use as the expected lead content: \to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)

8 0
3 years ago
I NEED HELP ASAP I WILL GIVE BRAINLIST
posledela

519.99(.0825) = 42.899

519.99 + 42.899 = $562.89

3 0
3 years ago
Read 2 more answers
Gino studied 3/4 hour for his test on Monday. He studied another 2/4 hour on Tuesday. How long did he study in all?
dybincka [34]
Gino studied for 5/4 hours in all. To get this, do 3+2 for the numerator and just put 4 as the denominator. (Four just stays the same the denominator is all fours. If you want more details just put it on comments.) Now you have the answer: 5/4 hours. 
8 0
3 years ago
The length of your classroom is about 3.5 x 10^2 inches. If the hallway is ten times as long as the classroom, what is the lengt
tatuchka [14]

Answer:

3.5x10^3

Step-by-step explanation:

3.5x10^2 = 350

350x10 = 3500

3500 = 3.5x10^3

8 0
3 years ago
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