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2 years ago

List the electron shell and the number of electrons in each shell

Chemistry

2 answers:

iren2701 [21]2 years ago

7 0

2, 8, 8, 16 and 32. They are the electron level le she'll beers and each never represents how much can fit in

dsp732 years ago

6 0

If you are only talking about the first 20 or so elements there is 2 in the first shell, 8 in the second and 8 in the third, but the 3rd shell can hold 18 but for early elements it jumps to the fourth shell after 8

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When a polypeptide is in its native conformation,there are weak interactions between its R groups. However, when it is denatured

Marina86 [1]

Answer:

In the unfolded polypeptide, there are ordered solvation shells of water around the protein

groups. The number of water molecules involved in such ordered shells is reduced when the protein

folds, resulting in higher entropy. Hence, the lower free energy of the native conformation.

Explanation:

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3 years ago

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Dmitry_Shevchenko [17]

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2 years ago

A home solar energy storage unit uses 4.75 ✕ 102 L of water for storing energy. On a sunny day, the water absorbed 2.75 ✕ 104 kJ

Sav [38]

Answer : The water's temperature change will be, $13.85^oC$

Explanation : Given,

Density of water = 0.998 g/mL

Volume of water = $4.75\times 10^2L=4.75\times 10^5mL$

(conversion used : 1 L = 1000 mL)

Specific heat of water = $4.184J/g^oC$

Heat absorbed = $2.75\times 10^4kJ=2.75\times 10^7J$

(conversion used : 1 kJ = 1000 J)

First we have to determine the mass of water.

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}$

$\text{Mass of water}=(0.998g/mL)\times (4.75\times 10^5mL)=474050g$

Now we have to calculate the change in temperature of water.

Formula used :

$Q=m\times C_w\times \Delta T$

where,

Q = heat absorbed by water

m = mass of water

$C_w$ = specific heat of water

$\Delta T$ = change in temperature

Now put all the given value in the above formula, we get:

$2.75\times 10^7J=474050g\times 4.184J/g^oC\times \Delta T$

$\Delta T=13.85^oC$

Therefore, the water's temperature change will be, $13.85^oC$

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3 years ago

4. Write the chemical formulas for the following compounds:

IRISSAK [1]

Lithium oxide ( Li2O)
Carbon monoxide ( CO )
Carbon tetrachloride ( CCl4 )
Nitrogen trifluoride ( NF3 )
Calcium chloride ( CaCl2)

4 0

2 years ago

A solution of 400mg of optically active 2-butanol in 10 mL of water, placed in a 20 cm cell shows an optical rotation of 40o. Wh

labwork [276]

Answer:

Specififc rotation [∝] = 0.5° mL/g.dm

Explanation:

Given that:

mass = 400 mg

volume = 10 mL

For a solution,

The Concentration = mass/volume

Concentration = 400/10

Concentration = 40 g/mL

The path length l = 20 cm = 2 dm

Observed rotation [∝] = + 40°

Specififc rotation [∝] = ∝/l × c

where;

l = path length

c = concentration

Specififc rotation [∝] = (40 / 2 × 40)

Specififc rotation [∝] = 0.5° mL/g.dm

3 0

2 years ago