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sleet_krkn [62]
3 years ago
15

Battery acid has a density of 1.285 g/mL and contains 38.0% sulfuric acid by mass. The car battery contains 1.45 L of battery ac

id. What is the mass of the sulfuric acid in a car battery?
Chemistry
1 answer:
larisa86 [58]3 years ago
5 0

Answer: 708.2 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Given : 38 g of H_2SO_4 is dissolved in 100 g of solution.

Density of solution = 1.285 g/ml

Volume of solution = \frac{mass}{density}=\frac{100g}{1.285g/ml}=77.8ml

Thus if 77.8 ml of H_2SO_4 contains = 38 g of H_2SO_4

1.45L= 1450 ml of H_2SO_4 contains = \frac{38}{77.8}\times 1450=708.2 g of H_2SO_4

Therefore, the mass of the sulfuric acid in a car battery is 708.2 g

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D) energy required to remove a valence electron

Explanation:

The ionization energy is the energy required to remove a valence electron from an element.

Different kinds of atoms bind their valence electrons with different amount of energy.

  • To remove the electrons, energy must be supplied to the atom.
  • The amount of energy required to remove the an electron in the valence shell is the ionization energy or ionization potential.
  • The first ionization energy is the energy needed to remove the most loosely bound electron in an atom in the ground state.
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HURRRYYY <br> in a chemical reaction you will always have an excess reactant. true or false?
just olya [345]

Answer:

It's False

Explanation:

In a chemical reaction, reactants that are not used up when the reaction is finished are called excess reagents. The reagent that is completely used up or reacted is called the limiting reagent, because its quantity limits the amount of products formed.

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A 100g sample of Carbon-14 has a half-life of 5 years. How much Carbon-14 is left after 10 years?
attashe74 [19]

Answer: The amount of carbon-14 left after 10 years is 25 g

Explanation:

Formula used :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives = ?

a_o = Initial amount of the reactant = 100 g

n = number of half lives =\frac{\text {given time}}{\text {half life}}=\frac{10}{5}=2

Putting values in above equation, we get:

a=\frac{100g}{2^2}

a=\frac{100g}{4}=25g

Therefore, the amount of carbon-14 left after 10 years is 25 g

6 0
3 years ago
A 25.0 mLsample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 37.5
matrenka [14]

Answer:

0.263M of CH₃COOH is the concentration of the solution.

Explanation:

The reaction of acetic acid (CH₃COOH) with NaOH is:

CH₃COOH + NaOH → CH₃COO⁻Na⁺ + H₂O

<em>1 mole of acetic acid reacts per mole of NaOH to produce sodium acetate and water.</em>

<em />

In the equivalence point, moles of acetic acid are equal to moles of NaOH and moles of NaOH are:

0.0375L × (0.175 moles / L) = 6.56x10⁻³ moles of NaOH = moles of CH₃COOH.

As the sample of acetic acid had a volume of 25.0mL = 0.025L:

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3 years ago
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