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mixas84 [53]
3 years ago
13

Unknown halogen X2 was added to each of two test tubes which contained aqueous NaCl and aqueous NaI, respectively. When hexane w

as added to the test tubes, an orange color developed in the top layer of the first test tube, while purple developed in the second.
a. Identify X2.
b. Write a balanced equation for each reaction which occurred.
Chemistry
1 answer:
weeeeeb [17]3 years ago
7 0

Answer:

Br_2

Explanation:

The compound X_2 is Br_2.

The reaction included are:

Br_2+NaCl--> No\ reaction  (because  bromine is less reactive than chlorine)

But , because of hexane the solution get dilute and its color changes to orange.

Now, NaI is added and we know Br is more reactive than I.

Therefore it replace it.

Reaction: Br_2+NaI-->NaBr+I_2

Purple color develop due to formation of Iodine.

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it is important to check the conductivity and pH of pure water to:


1- to check the purity of water and if it healthy or not , and the water source.


2- we have to measure the PH to know the alkalinity or acidity of water. If the PH > 7 so it is acidic , if PH < 7 so it is alkaline.


3- we have to measure the conductivity of the water as it is an indication for the impurity level. and it shouldn't be high to keep the water healthy.



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What does the δ– symbol mean on a water diagram?
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a or

Explanation:

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Which type of matter has a definite composition througout and is made of more than on type of element
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Explanation:

It has a definite composition throughout and can be made of more than one type of element.

4 0
3 years ago
A 0.885 M solution of KBr whose initial volume is 82.5 mL has more water added until its concentration is 0.500 M. What is the n
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Answer:

V_2=146mL

Explanation:

Hello there!

In this case, since the equation for the calculation of dilutions is:

M_1V_1=M_2V_2

Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:

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4 0
3 years ago
A container initially holds 1.24mol of hydrogen gas and has a volume of 27.8L. Hydrogen gas was added to the container, and the
Fantom [35]

Answer:

After increasing the volume, we have 1.81 moles of hydrogen gas in the container

Explanation:

Step 1: Data given

Number of moles hydrogen gas (H2) = 1.24 moles

Volume of hydrogen gas (H2° = 27.8 L

The final volume is increas to 40.6 L

Step 2: Calculate the new number of moles

V1/n1 = V2/n2

⇒with V1 = the initial volume = 27.8 L

⇒with n1 = the initial number of moles H2 = 1.24 moles

⇒with V2 = the final volume = 40.6 L

⇒with n2 = the new number of moles = TO BE DETERMINED

27.8L / 1.24 moles = 40.6 L / n2

n2 = 40.6 / (27.8/1.24)

n2= 1.81 moles

After increasing the volume, we have 1.81 moles of hydrogen gas in the container

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