In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).
Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol
To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C=

%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%
it is most likely a beaker, beacuse 300ml is quite a large volume. Otherwise, it would be a measuring cylinder or pippette
Cr2(CO3)3 is Chromium (III) Carbonate or Chromic Carbonate.
It is composed of Chromium, Carbon, and Oxygen. Chromium has 2 atoms, Carbon has 3 atoms, and Oxygen has 9 atoms.
This compound is composed of 36.6% Chromium, 12.7% Carbon, and 50.7% Oxygen.
Answer: The pressure required is 0.474 atm
Explanation:
Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.
(At constant temperature and number of moles)
The equation is,

where,
= initial pressure of gas = 1.0 atm
= final pressure of gas = ?
= initial volume of gas = 
= final volume of gas =
(
Now put all the given values in the above equation, we get:


The pressure required is 0.474 atm