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Snowcat [4.5K]
3 years ago
7

Please help I cant find the answer anywhere

Mathematics
1 answer:
DedPeter [7]3 years ago
5 0
I am going to answer these from left to right.
Corresponding
None
Corresponding
Alternate exterior
Alternate interior
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An angle with its vertex on the circle and with sides that are chords of the circle is called a(n) ______angle. A. vertical B. i
Zielflug [23.3K]

Answer:

The answer is B. inscribed

Step-by-step explanation:

3 0
4 years ago
Brainliest answer to the right answer and 30 points!
timofeeve [1]
10.5^2 + 20.8^2 = 110.25 + 432.64 = 542.89
23.3^2 = 542.89 
Right triangle
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20.1^2 = 524.41
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8 0
3 years ago
6(5m - 4) <br> A. 30m - 4<br> B. 30m - 24<br> C. 30m + 24<br> D. 54m
mixas84 [53]

Answer:

6(5m-4)

=30m -24

option B

6 0
3 years ago
Adult tickets for the school play cost 6 dollars in student tickets cost 4 dollars. 20 more adult tickets were sold and student
Tasya [4]

Answer: 35 adult tickets and 15 student tickets were sold.

Step-by-step explanation:

Let x represent the number of adult tickets that were sold.

Let y represent the number of student tickets that were sold.

20 more adult tickets were sold and student tickets. It means that

x = y + 20

Adult tickets for the school play cost 6 dollars and student tickets cost 4 dollars. If $270 was collected, it means that

6x + 4y = 270- - - - - - - - - - - 1

Substituting x = y + 20 into equation 1, it becomes

6(y + 20) + 4y = 270

6y + 120 + 4y = 270

6y + 4y = 270 - 120

10y = 150

y = 150/10

y = 15

x = y + 20 = 15 + 20

x = 35

5 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
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