Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
26
Step-by-step explanation:
Use the Pythagorean Theorem: 
The answer is -5
Explanation: Divide 2 to get rid of the top number. It looks like this
-10. 2y
___. ___
2. 2
What this does is remove the two from the Y and sets it by itself. Then you divide the -10, and the answer is -5
What is the question?
Step-by-step explanation:
Step-by-step explanation:
The key rule is: to round up the number one digit to the left has to be the number 5 or more, else it rounds down.
23.827 rounds up because the 8 is more than 5.
1.218 rounds down because 2 is less than 5.
24-1= 23
