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3 years ago

11

HELP! In rectangle DEBC, Eb = 12 and Cb =4. What is the approximate distance from point E to point C? (I’m giving away robux to

who ever helps me)

1 answer:

pav-90 [236]3 years ago

4 0

Answer:

12.65

Explanation:

By using pythagoras theorem :

(CE)^2 = (EB)^2 + (CB)^2

= (12)^2 + (4)^2

= 144+16

CE = (Root sign)160

= Approx. 12.64 rounded off to 12.65

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