Use a calculator you should get 36.156
Answer:
5
Step-by-step explanation:
Evaluate (h + k)(x) then substitute x = 2 into the result
(h + k)(x) = h(x) + k(x)
h(x) + k(x) = x² + 1 + x - 2 = x² + x - 1, thus
(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5
If you meant to write (x-2)^2 + (y-6)^2 = 4, then the center is (2,6). The statement would be true.
This is because the general form (x-h)^2 + (y-k)^2 = r^2 describes a circle centered at (h,k) with radius r. In this case, h = 2, k = 6, r = 2. Note how r^2 = 4 so r^2 = 2^2 leads to r = 2.
Answer:
It is C cause I know
Step-by-step explanation:
7. J(-4,4) K(2,-4)
8.L(-2,2) M(1,2)
9.N(1,-3) O(4,-3)
10. P(-2,-2)