Answer:
or 
Step-by-step explanation:
The given equation is

Let us treat this as a quadratic equation in
.
where 
The solution is given by the quadratic formula;

We substitute these values into the formula to obtain;





or 
or 
or 
or 
If y+6=15, then y=9. (9+6)divided by 3 would be 5, not 15.
Piper rockelle and sawyer reposted us on the devil in squad and part b you guys are you
9 squares because if there are 18 triangles in it then you divide 18 by 2 and get 9
Answer:
x<56
Step-by-step explanation:
Since the dot over 56 isn't filled in, the inequality doesn't include 56 (so we'll use < or > not
or
)
Now, let's look at the direction of the shading: is it going to the left of 56 or to the right?
This shading is to the left of 56, which indicates that it's all of the numbers less than 56.
As said above, the inequality doesn't include 56
therefore, it will be x<56 (x is less than 56, and 56 is not included)
hope this helps!