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4 years ago

Please write an algebraic proof showing that (a+b)(a-b)=a^2-b^2

Mathematics

1 answer:

murzikaleks [220]4 years ago

5 0

Answer:

(a+b)(a-b)

a(a - b) + b (a - b)

= a^2 - ab + ab - b^2

=a^2 - b^2

Step-by-step explanation:

distribute a(a-b)
distribute b(a-b)
add like-terms

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Suppose there are 20 questions on a multiple choice test.if 25% of the answers are choice b how many of the answers are not choi

zvonat [6]

Answer:

are not choice b 75%

75/100 *20 = 1500/100=15

Step-by-step explanation:

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4 years ago

Find the slope of the line through each pair of points

NNADVOKAT [17]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

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$(-13,\ -10)\to x_1=-13,\ y_1=-10\\(16,\ 16)\to x_2=16,\ y_2=16$

substitute:

$m=\dfrac{16-(-10)}{16-(-13)}=\dfrac{16+10}{16+13}=\dfrac{26}{29}$

96)

$(6,\ -16)\to x_1=6,\ y_1=-16\\(-15,\ 9)\to x_2=-15,\ y_2=9$

substitute:

$m=\dfrac{9-(-16)}{-15-6}=\dfrac{25}{-21}=-\dfrac{25}{21}$

97)

$(12,\ -11)\to x_1=12,\ y_1=-11\\(14,\ -12)\to x_2=14,\ y_2=-12$

substitute:

$m=\dfrac{-12-(-11)}{14-12}=\dfrac{-12+11}{2}=-\dfrac{1}{2}$

OK. I think you already know how to solve it. I will give short solutions now.

98)

$m=\dfrac{15-(-3)}{8-(-14)}=\dfrac{18}{22}=\dfrac{9}{11}$

99)

$m=\dfrac{3-(-5)}{-7-3}=\dfrac{8}{-10}=-\dfrac{4}{5}$

100)

$m=\dfrac{-8-8}{-11-0}=\dfrac{-16}{-11}=\dfrac{16}{11}$

101)

$m=\dfrac{13-(-5)}{-13-(-13)}=\dfrac{18}{0}!!!-\boxed{NOT\ EXIST}$

102)

$m=\dfrac{18-1}{-10-2}=\dfrac{17}{-12}=-\dfrac{17}{12}$

103)

$m=\dfrac{19-14}{7-(-17)}=\dfrac{5}{24}$

104)

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3 years ago

Which equation has an x-intercept of 5 and a y-intercept of -5?

AURORKA [14]

Answer: y=5x-5

Step-by-step explanation:

3 0

3 years ago

Very important part 2 ! Thank youuuuu !!!!!!!!!!

Sunny_sXe [5.5K]

Answer: Neither linear nor exponential (choice B)

Through interpolation, a graphing calculator, or trial and error, you can find the function to be f(x) = 2x^2. This is a polynomial function. It is not linear as it graphs out a curved parabola. It's not exponential either since the exponent isn't a variable. This also can be considered a power function.

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4 years ago

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Flura [38]

Answer:

Step-by-step explanation:

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3 years ago