Question

GUYS PLEASE HELP ME PLEASE HELP HELP PLEASE HELP ASAP GUYS HELP!!!!!

Answer 1

Answer:

$SA=5\ yd^2$

Step-by-step explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four triangular faces

so

$SA=b^2+4[\frac{1}{2}(b)(h)]$

we have

$b=1\ yd\\h=2\ yd$

substitute

$SA=1^2+4[\frac{1}{2}(1)(2)]$

$SA=5\ yd^2$