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3 years ago

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Which of the following is true of the electrons in the Bohr model of an atom?

1 answer:

NARA [144]3 years ago

6 0

Answer:

They exist at specific energy levels

Explanation:

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What does C12 H22 O11 phSO mean

ioda

Those are basically molecular formula. Which is Table sugar or cane sugar. Generally called sucrose.

8 0

3 years ago

How do you measure moles

wlad13 [49]

Answer:

Answers may vary

Explanation:

Mol is the amount of molecules in something. Mol are similar to donuts, if you have a dozen of something you have 12 of them. If you have a mol of Hydrogen gas you 6.02•10^23 molecules of Hydrogen gas. If you are taking a chemistry class you will probably receive questions involving converting grams to mol and vice versa.

Converting Grams to Mol:

grams of x•(1/molecular mass of x)

note: you can find molecular mass of x by looking at the masses of the elements you need to add up in the periodic table

Converting Mol to Grams:

mol of x•(molecular mass of x)

6 0

3 years ago

Read 2 more answers

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

3 years ago

Pls hurry I need to have this ASAP

tankabanditka [31]

Answer:

The image is too blurry to see anything

Explanation:

Please upload a better image

3 0

2 years ago

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Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is

Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal = $C_{134}H_{96}O_{9}NS$

Molecular mass of coal = $(134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm$

Let’s calculate the mass of nitrogen in coal

$Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}$

$Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%$

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = $4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons$

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0

3 years ago

Read 2 more answers