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3 years ago

Electrons involved in bonding between atoms are __________________

1 answer:

5 0

The name given to these electrons are that they are valence electrons or binding electrons as these are directly involved in chemical Bonding and allow for different compounds to be made.

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Can you balance 12 blocks on the 3x2 platform

Jobisdone [24]

Yes, it is possible to go do because it would be 2 stacks of 6

3 0

2 years ago

The number of O atoms in 6.15 g of Al(PO 4 ) 3 (molar mass=122.00 g/mol) is

pickupchik [31]

Soowowowowlw,was the day that I was just trying to find out

6 0

3 years ago

PLS HELP THE QUESTION IS ON THE PICTURE

IceJOKER [234]

Concepts used:

1 mole of an element or a compound has 6.022 * 10²³ formula units

So, we can say that: Number of formula units = number of moles * 6.022*10²³

number of moles of an element or a compound = given mass/molar mass

__________________________________________________________

003 - Number of CaH₂ formula units in 6.065 grams

Number of Moles:

We know that the molar mass of CaH₂ is 42 grams/mol

Number of Moles of CaH₂ = given mass/molar mass

Number of moles = 6.065 / 42

Number of moles = 0.143 moles

Number of Formula units:

Number of formula units = number of moles * 6.022*10²³

= 0.143 * 6.022 * 10²³

= 0.86 * 10²³ formula units

__________________________________________________________

004 - Mass of 6.34 * 10²⁴ formula units of NaBF₄

Number of Moles:

We mentioned this formula before:

Number of formula units = number of moles * 6.022*10²³

Solving it for number of moles, we get:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variable

Number of moles = 6.34 * 10²⁴ / 6.022*10²³

Number of moles= 10.5 moles

Mass of 10.5 moles of NaBF₄:

Molar mass of NaBF₄ = 38 grams/mol

Mass of 10.5 moles = 10.5 * molar mass

Mass of 10.5 moles = 10.5 * 38

Mass = 399 grams

__________________________________________________________

005 - Number of moles in 9.78 * 10²¹ formula units of CeI₃

Number of Moles:

We have the formula:

Number of moles = Number of Formula units / 6.022* 10²³

replacing the variables

Number of Moles = 9.78 * 10²¹ / 6.022*10²³

Number of Moles = 1.6 / 10²

Number of Moles = 1.6 * 10⁻² moles OR 0.016 moles

3 0

3 years ago

When h2o is added to a compound in a chemical equation, a new compound can be formed via what type of reaction?

Scorpion4ik [409]

When water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.

<h3>What is hydrolysis reaction?</h3>

There are so many kinds of reaction in chemistry we know that a chemical reaction occurs between reactant molecules in order to yield products in the reactants.

The hydrolysis reaction is a breaking up reaction. In a hydrolysis reaction, water is used to break up a molecule. Hence in a hydrolysis reaction water could be regarded as one of the reactants in the reactions going on in the system.

We know that a hydrolysis is a reaction in which water reacts with another reactant molecule to yield products in the reaction. Thus, when water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.

Learn more about hydrolysis:brainly.com/question/12237250

#SPJ1

5 0

2 years ago

An unknown radioactive substance has a half-life of 3.20hours . If 46.2g of the substance is currently present, what mass A0 was

iogann1982 [59]

Answer:

a) a0 was 46.2 grams

b) It will take 259 years

c) The fossil is 1845 years old

Explanation:

An unknown radioactive substance has a half-life of 3.20hours . If 46.2g of the substance is currently present, what mass A0 was present 8.00 hours ago?

A = A0 * (1/2)^(t/h)

⇒ with A = the final amount = 46.2 grams

⇒ A0 = the original amount

⇒ t = time = 8 hours

⇒ h = half-life time = 3.2 hours

46.2 = Ao*(1/2)^(8/3.2)

Ao = 261.35 grams

Americium-241 is used in some smoke detectors. It is an alpha emitter with a half-life of 432 years. How long will it take in years for 34.0% of an Am-241 sample to decay?

t = (ln(0.66))-0.693) * 432 = 259 years

It will take 259 years

A fossil was analyzed and determined to have a carbon-14 level that is 80% that of living organisms. The half-life of C-14 is 5730 years. How old is the fossil?

t = (ln(0.80))-0.693) * 5730 = 1845

The fossil is 1845 years old

7 0

3 years ago