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otez555 [7]
3 years ago
15

How many molecules are there in 79g of Fe2O3?

Chemistry
1 answer:
weqwewe [10]3 years ago
6 0
There are approximately 160 grams in 1 mol of fe203 molecules therefore there would be 79/160 = 0.49375 mols of fe203 molecules in 79 grams therefore 5 atoms in total for each molecule of fe203 therefore 79/160 *5 =79/32=2.46875 mols in atoms
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MgSO4equilibrate the hydrolysis reaction
maksim [4K]

Answer:

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Explanation:

in my training, this wud mean destruction of water, or loss of water in the human body.

2 equalibrate, takes sodium chloride, to retain fluids by IV.

3 0
3 years ago
4AI + 30 ---&gt;<br> ---&gt; 2A1 O
Aleks04 [339]

Explanation:

Answer is 4Al + 3O2 =>2Al2O3

I hope it's helpful!

5 0
2 years ago
How are vibrations different between bigger sizes rubber bands and smaller sized rubber bands?
arlik [135]
Assuming the kind of vibration you are talking about is the kind where you stretch the rubber band between two points and then "twang" it, then the answer is fairly complex. What happens when you cause the vibrations to start is you make something called a "standing wave". In a standing wave, each particle in the rubber band has a certain amount of energy which causes it to move backwards and forwards, the particles with more energy have a larger "amplitude" (how much they move), and of course the particles with less energy have a smaller amplitude. Now a standing wave has two main components: The amplitude, and the frequency. The amplitude of the whole wave refers to the largest amplitude any particles has. The frequency refers to how often it takes for one of the particles to move between the two furthest away points it can be.
To compare rubber bands, you must remember to keep certain things constant. If you're looking at their vibrations, the amount of energy you use to "twang" the rubber band should be the same each time you twang it (which is the same as applying the same force each time you twang it).

A larger rubber band has more area over which to spread the energy, as well as it has more mass for the energy to move, so the vibrations will have smaller amplitudes, and smaller frequencies, overall vibrating less and with smaller vibrations. 
5 0
3 years ago
2. If a gas at 500 mL has a temperature of 45°C, then what is the new volume when the temperature is increased to 65°C? Show you
OLEGan [10]

Answer:

V2= 531.4 ml

Explanation:

T1= 273+45 °C= 318 Kelvin

T2= 273+65 °C= 338 Kelvin

V1= 500ml *( 0.001L/1ml)= 0.5 Liters

V2= \frac{V1 * T2}{T1}= \frac{0.5 L * 338K}{318K} = 0.5314465409 Liters* (1 ml/0.001 L)= 531.4 ml

8 0
2 years ago
(05.01 LC)
pav-90 [236]
The answer to your question is A.
7 0
3 years ago
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