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Oksanka [162]
3 years ago
7

Given that 7.25 moles of carbon monoxide gas are present in a container of volume 11.90 L, what is the pressure of the gas (in a

tm) if the temperature is 87°C?
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:17.955atm

Explanation:Pv=nrt

P= nrt/v

P= 7.25*0.08205*360/11.90

P= 214.1505/11.90

P=17.995atm

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A saline solution with a mass of 400 g has 30 g of NaCl dissolved in it. What is the mass/mass percent concentration of the solu
maria [59]
(g solute/g solution)*100 = % mass/mass

30 g / 400 * 100 

0,075 * 100

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hope this helps!

3 0
3 years ago
2MG+O2 ...........2MGO
Galina-37 [17]
Mg + 1/2 O2 → MgO

1 mol = 24 g of Mg

X mol = 12 g of Mg

x = 0.5 moles of Mg

Mg :MgO = 1:1 (coefficient from equations using mole ratio)

So

0.5 moles of MgO

1 mol MgO = (24+16) g = 40 g

0.5 moles of MgO = 0.5 × 40

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5 0
3 years ago
What is ph of a solution that contains 1.32 grams of nitric acid hno3 dissolved in 750 ml of water​
Agata [3.3K]

what is the pOH of the solution? 10.25 is the answer

3 0
3 years ago
Find the volume in milliliters of 2.00 mol of an ideal gas at 36°C and a pressure of 1120 torr.
hram777 [196]

Answer:

V = 34430 mL

Explanation:

Given data:

Volume in mL = ?

Number of moles of gas = 2.00 mol

Temperature = 36°C (36+273= 309K)

Pressure of gas = 1120 torr

Solution:

Formula:

PV = nRT

V = nRT/P

V = 2.00 mol ×62.4 torr • L/mol · K × 309K / 1120 torr

V = 38563.2 torr • L / 1120 torr

V = 34.43 L

L to mL

34.43 L ×1000 mL / 1 L

34430 mL

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Answer:

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Explanation:

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