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3 years ago

Three times the sum of a number and four is equal to five times

Mathematics

2 answers:

Morgarella [4.7K]3 years ago

7 0

1) correctly translates the statement

erik [133]3 years ago

5 0

First, "the sum of a number and four" is x+4.
Three times (x+4) is 3(x+4). It's also the left side of the equation.

Second, "five times the number" is 5x.
The result will then be "decreased by two", which is 5x-2. It's also the right side of the equation.

Therefore, option (1) is the correct answer.

Hope this would help :))

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I got stuck here on this question... this is Algebra 2 btw

svetlana [45]

I don’t think this is algebra 2 but ok

I used the formula (32°F − 32) × 5/9 = 0°C (but ofc replaced the numbers with 99)

Yeah and i rounded 98.6 to 99. 99 Fahrenheit is 37.2222... so i rounded it down to 37. So i think the answer is 37.

3 0

2 years ago

Solve 1/p+1/s=1 for p

jekas [21]

Answer:

Step-by-step explanation:

Multiply through by the L. C. M which is PS.

1/p*ps+1/s*ps=1*ps

P+p=ps

2p=ps

Divide both sides by 2

2p/2=ps/2

P=ps/2

3 0

2 years ago

A rectangular field has the area equal to that of a square field of side 60m.if the breadth of the rectangular field is 32m, fin

V125BC [204]

Given -

Area of rectangular field = Area of square field
side of square = 60m
breadth of the rectangular field = 32m

To find -

length of the rectangular field

Solution -

Area of square = side × side = (60 × 60)m² =

Area of square =3600m²

Hence,

Area of rectangular field = Area of square field = 3600m²

Area of rectangular field = l × b = 3600m²

=> l × 32m = 3600m²

=> l = $\sf{\frac{3600}{32}\:m}$

=> l = 112.5m

so, the length = 112.5m

5 0

2 years ago

A book claims that more hockey players are born in January through March than in October through December. The following data sh

denis-greek [22]

Complete question :

Birth Month Frequency

January-March 67

April-June 56

July-September 30

October-December 37

Answer:

Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.

Step-by-step explanation:

Observed value, O

Mean value, E

The test statistic :

χ² = (O - E)² / E

E = Σx / n = (67+56+30+37)/4 = 47.5

χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295

Degree of freedom = (Number of categories - 1) = 4 - 1 = 3

Using the Pvalue from Chisquare calculator :

χ² (18.295 ; df = 3) = 0.00038

Since the obtained Pvalue is so small ;

P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.

5 0

2 years ago

Lines AB and CD are parallel. If the measure of angle

BARSIC [14]

Answer:

Angles W, Z, M, P are 111°

Angles Y, X, O, N are 69°

3 0

2 years ago