Answer:B
Step-by-step explanation:
All you have to do is multiply
<span>Use the Pythagorean Theorem to solve. This will be a right triangle:
=
Let the slope = the hypotenuse = c
Let one side = a=8
Let the other side =b =15
Plug-in the values and solve for the c-term
Check you answer by plugging the value of "c" back into the orignial equation and solve.
.
=
=
=
=
=
17=c
.
Check by plugging into the original equation and solve.
=
=
289=289 [checks out]</span>
<h3>Problem Solution</h3>
Assuming the spool is a cylinder and the circumference we're winding around is that of a circle with the given area, we can write the relation between circumference and area as
... C = 2√(πA)
10 times the circumference is then
... 10C = 20√(π·20 cm²) = 40√(5π) cm ≈ 159 cm
<h3>Formula Derivation</h3>
The usual formulas for circumference and area are
... C = 2πr
... A = πr²
If we multiply the area formula by π and take the square root, we get
... πA = (πr)²
... √(πA) = πr
Multiplying this by 2 gives circumference.
... C = 2√(πA) = 2πr
Answer:
D.
Step-by-step explanation:
Statistics has a lot of usage in business.
Using statistics as well as statistical tools helps in the provision of data to be used for business analysis. With available data we can get patterns in a a large database. Statistics can be used for auditing, as in question option b. For option c, statistics can be used for making business forecasts after the careful observation of trends and patterns that are in the data.
Option d does not make use of statistics. It has nothing to do with statistics neither does it have a computational feature.
Therefore, d.) questioning the executive's strategic decision is the answer to this question
Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
