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ivolga24 [154]
3 years ago
6

Need help with homework plz and thank u :)

Mathematics
2 answers:
AleksAgata [21]3 years ago
6 0

Answer:

B

Step-by-step explanation:

The zeros are where the function crosses the x-axis. In this case, it is 5/2 and -3, which eliminates options C and D. Next, the y-intercept is the point as to where the function crosses the y-axis. Here, it is (0,15), but does not help us to narrow down our options. Finally, the maximum is the highest y-value that the function touches. If you observe the graph at its highest point, it can be inferred that it's y-value is slightly above 15, and so it is at 15.1 (x-value has no importance in this context).

Makovka662 [10]3 years ago
4 0
Answer is B! hope this helped!
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What arithmetic variables look like
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Answer:

LETTERS

Step-by-step explanation:

In Arithmetic, variables look like LETTERS.

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3 years ago
A line has the equation 3x ? 4y = 1. Choose the equation of a line that is parallel to the given line.
cupoosta [38]

Answer:

Find a line which also has 3/4 as the slope or 3x - 4y in standard form.

Step-by-step explanation:

If the line is 3x - 4y = 1 then the line which is parallel will have the same coefficients of x and y. Parallel lines never cross and to ensure this have the same slope. The slope is a ratio which can be solved for in an equation using the coefficients of x and y. Here the slope is:

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y = 3/4x - 1/4.

Find a line which also has 3/4 as the slope or 3x - 4y in standard form.

7 0
3 years ago
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Simora [160]

Answer:

I think your answers are right.

Step-by-step explanation:

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8 0
3 years ago
1 Point
I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

\text { Volume of a cylinder }=\pi r^{2} h

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e  

\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}

<em><u>Ratio for the volumes of two cylinders</u></em>

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}

Cancelling the common terms, we get

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)

Substituting we get,

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}

\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}

Hence, the ratio of volume of two cylinders is 8 : 27

7 0
3 years ago
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AVprozaik [17]
Well, some integers can be irrational, but not all! :) 
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