Answer:
16
Step-by-step explanation:
The mean of a group of values is calculated as
mean = 
Given 5 numbers with a mean of 12, then
= 12 ( multiply both sides by 5 )
sum = 60
let the number removed be x , then
= 11 ( multiply both sides by 4 )
60 - x = 44 ( subtract 60 from both sides )
- x = - 16 ( multiply both sides by - 1 )
x = 16
The number removed was 16
Answer:
The measure of the angle JKG is:
m∠JKG = 56°
Step-by-step explanation:
<u>Given</u>
m∠JKG = 76-2x
m∠FHK = 6x-4
J is a midpoint of the segment FG and K is a midpoint of the segment GH.
<u>To determine</u>
m∠JKG = ?
Given that J is a midpoint of the segment FG and K is a midpoint of the segment GH. Thus, making two similar triangles, ΔJGK and ΔFGH
We know that two triangles are similar if the only difference is size. So, the angles remain the same.
so m∠JKG and m∠FHK are equal.
i.e.
m∠JKG = m∠FHK
substitute m∠JKG = 76-2x and m∠FHK = 6x-4
76-2x = 6x-4
6x+2x = 76 + 4
8x = 80
divide both sides by 8
8x/8 = 80/8
x = 10
Therefore, the value of x = 10
As
m∠JKG = 76-2x
substitute x = 10
m∠JKG = 76 - 2(10)
= 76 - 20
= 56°
Therefore, measure of the angle JKG is:
m∠JKG = 56°
Answer:x>2
Step-by-step explanation:
4x/4>8/4
Answer:
I think it's either Wednesday or Sunday.
Step-by-step explanation:
Answer:
The number of students that bring their lunches is 12
Step-by-step explanation:
Let
x -----> the number of students that bring their lunches
y -----> the total number of students in a class
we know that
The number of students that bring their lunches divided by the total number of students in a class must be equal to 3/8
-----> equation A
-----> equation B
substitute the value of y in equation A and solve for x
therefore
The number of students that bring their lunches is 12
