The formula we need is
, where <em>v</em>₀ is the starting velocity and <em>h</em>₀ is the initial height. Using the velocity and starting height from our problem we have
. The path of this rocket will be a downward facing parabola, so there will be a maximum. This maximum will be at the vertex of the graph. To find the vertex we start out with
, which in our case is
. It will take 5 seconds for the rocket to reach its maximum height. Plugging this back into our formula gives us
The rocket's maximum height is 400 feet.
We set our formula equal to zero to find the time it takes to hit the ground, then we factor:
Using the zero product property, we know that either -16t =0 or t-10=0. When -16t=0 is at t=0, when the rocket is launched. t-10=0 gives us an answer of t=10, so the rocket reaches the ground again at 10 seconds.
Answer: 45
Step-by-step explanation:
A right isosceles triangle can only ever have two equal sides, since he sum of the three angles of any triangle is equal to 180 degrees, do the quick math of 180 - 90 = 90, then 90/2 = 45. Both remaining angles of the triangle are 45 degrees, including x, and when you add all angles together 90 + 45 + 45 it equals 180 degrees.
Answer:
6in
Step-by-step explanation:
Midsegment thrm: half the sum if the lengths of the bases
32= 1/2(58+x)
32=29+ 1/2x
3= 1/2x
6=x
HE WILL NEED 12 FEET WICH ROUNDED TO THE NEAREST FOOT IS 10
11 : 12.....11 + 12 = 23
boys : 11/23 * 460 = 5060/23 = 220 <===
girls : 12/23 * 460 = 5520/23 = 240