The statement correct about bonding is the release of energy in bond formation, and is exothermic. Thus, option C is correct.
The bonds have been defined as the sharing of electrons between atoms for the stabilization and forming compounds. The formation and breaking of the bond results in the absorption and release of the energy.
<h3>Endothermic and Exothermic reaction</h3>
The reaction in which the energy has been released has been termed as exothermic reaction. The reaction in which energy is absorbed is termed as endothermic system.
The bonds are stable, and to break the bond energy has to be provided to the system. The energy will result in the delocalization of electrons and thereby breaking of bonds.
Since energy has been absorbed by the system during breaking of bonds, the reaction has been an endothermic reaction.
The formation of the bond has been releases the energy in the system and is an exothermic reaction. Thus, option C is correct.
Learn more about bonding, here:
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The Step that is Usually done right before the experimentation in the Scientific Method is Developing a Hypothesis and asking a Question.
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~Izzy
Answer: The empirical formula for the given compound is 
Explanation : Given,
Mass of O = 0.370 g
Mass of N = 0.130 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Oxygen = 
Moles of Nitrogen = 
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00928 moles.
For Oxygen = 
For Nitrogen = 
Step 3: Taking the mole ratio as their subscripts.
The ratio of O : N = 2 : 1
Hence, the empirical formula for the given compound is
Equation a. C3H8(g) + O2(g) → CO2(g) + H2O(g) + 2220 kj
is endothermic. + 2220 kj
Equation b. 2 Na(s) + Cl2(g) → 2 NaCl(s) + 819kJ
is also endothermic since the overall energy change is positive. + 819kJ
The equation c. PCl5(g) + 67kj → PCl3(g) + Cl2(g) is endothermic since it requires anergy to proceed.
