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Viefleur [7K]
3 years ago
12

When positive integer A, which has n digits, is multiplied by (n+2) , the product is a number with (n+1) digits, all of whose di

gits are (n+1) . How many instances of A exist?
Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

  A = 95238 (only)

Step-by-step explanation:

The question is equivalent to asking what n-digit number consisting only of the digit n will be divisible by n+1. Of the numbers 1, 22, 333, 4444, ... 999999999, the only one is 666666, which is divisible by 7.

The 5-digit integer A is 666666/7 = 95,238. There is only one instance of A.

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Answer:

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Step-by-step explanation:

I know the measurement of the other leg is about 11.5 cm. I know because I used the Pythagorean theorem.

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3 0
2 years ago
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nexus9112 [7]
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m \: < \: B = 45 \degree = m \: < \: C
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