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Viefleur [7K]
3 years ago
12

When positive integer A, which has n digits, is multiplied by (n+2) , the product is a number with (n+1) digits, all of whose di

gits are (n+1) . How many instances of A exist?
Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer:

  A = 95238 (only)

Step-by-step explanation:

The question is equivalent to asking what n-digit number consisting only of the digit n will be divisible by n+1. Of the numbers 1, 22, 333, 4444, ... 999999999, the only one is 666666, which is divisible by 7.

The 5-digit integer A is 666666/7 = 95,238. There is only one instance of A.

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Answer: D

Step-by-step explanation:

It seems there is two ways to solve this, remember that this is just one of them.

The triangle to the left is an isosceles triangle by definition. It is given that two of its sides are equal.

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This angle is opposite to Angle Y. Vertical angles are congruent, so Angle Y must be 70 degrees.

D is the answer.

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3 years ago
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Step-by-step explanation:

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Question 7 of 10
sergejj [24]

The product that is  undefined is known a CD, where C is a 3 x 1 matrix and D is a 1 x 2 matrix.

<h3>What is the matrix about?</h3>

Looking at the product of matrix, note that to multiply  the two matrix, the column of the first matrix needs to have the same or equal to the row of the 2nd matrix.

And in this case (propensity), it is not satisfied by the first  option because:

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O= 2 x 1  matrix

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