Answer: Option (D) is the correct answer.
Explanation:
An electric circuit works well when all the connections are complete but if any of the connections in the circuit is loose or disconnected then it is possible that current will not flow from the circuit.
Therefore, when Jenna removed one of the clips on the battery then circuit becomes incomplete and as a result there will no flow of current.
Thus, we can conclude that the electrical energy would stop because the circuit is incomplete.
<span>XY4Z2-->Square planar (Electron domain geometry: Octahedral) sp3d2
XY4Z-->Seesaw (Electron domain geometry: Trigonal bipyramidal) sp3d
XY5Z-->Square pyramidal (Electron domain geometry: Octahedral) sp3d2
XY2Z3-->Linear (Electron domain geometry: Trigonal bipyramidal) sp3d
XY2Z-->Bent (Electron domain geometry: Trigonal planar) sp2
XY3Z-->Trigonal pyramidal (Electron domain geometry: Tetrahedral) sp3
XY2Z2-->Linear (Electron domain geometry: Tetrahedral) sp3
XY3Z2-->T shaped (Electron domain geometry: Trigonal bipryamidal) sp3d
XY2-->Linear (Electron domain geometry: Linear) sp
XY3 Trigonal planar (Electron geometry: Trigonal planar) sp2
XY4-->Tetrahedral (Electron domain geometry: tetrahedral) sp3
XY5-->Trigonal bipyramidal (Electron domain geometry: Trigonal bipyramidal) sp3d
XY6-->Octahedral (Electron domain geometry: Octahedral) sp3d2</span>
<u>Answer;</u>
= 0.422 M
<h3><u>Explanation;</u></h3>
Molarity or concentration is the number of moles of a solute in 1 liter of a solution.
Therefore; Molarity = n/V ; where n is the number of moles and V is the volume of the solution in L.
Number of moles = Mass/molar mass
= 289 g/342.2965g/mol
= 0.844 Moles
Therefore;
Molarity = 0.844 moles/ 2L
= 0.422 M
it is sunlight and you can see its the first one
You can solve this by saying that there are 3 Cl for every 1 Al therefore a ratio of 1:3. If you have 12 Cl ions you can find how many Al ions there is
so (x)Al : 12 a unkown amount of Al ions gives you 12 Al ions from the ratio we know that we have 1 Al for 3 Cl therefore we can divide 12 by 3 to get the number of Al ions. The answer is 4 Al ions for 12 Cl ions.
Hope this helps :).
