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Ksenya-84 [330]
3 years ago
10

What does the Atomic Number tell you? the amounr of electronstprorons

Chemistry
1 answer:
tankabanditka [31]3 years ago
6 0

Answer

Atomic number or proton number tells us the number of protons found in the nucleus of every atom of that element

Explanation:

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7. Bananas contain potassium. Which form of potassium is most likely found in bananas or in nature? a. K atom b. K+ cation C. K-
bulgar [2K]

Answer:

B. K+cation

Explanation:

Not all that sure but hope it will help.

7 0
3 years ago
Are C-12, C-13, and C-14 all carbon isotopes?
kramer

Answer:

Yes, they are isotopes.

Explanation:

Isotopes are atoms with the same atomic number Z and a different mass number (A). That is, they differ in the number of neutrons (eg carbon 12, has 6 protons, 6 electrons, and 6 neutrons, carbon 13, 7 neutrons, and carbon 14 8 neutrons).

3 0
3 years ago
Read 2 more answers
An equilibrium mixture of PCl 5 ( g ) , PCl 3 ( g ) , and Cl 2 ( g ) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 To
antoniya [11.8K]

Answer: The new partial pressures of PCl_5,PCl_3\text{ and }Cl_2 when equilibrium is re-established are 223.4 torr, 6.82 torr and 26.4 torr respectively.

Explanation:

For the given chemical reaction:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of K_p for above reaction follows:

K_p=\frac{P_{PCl_5}}{P_{PCl_3}\times P_{Cl_2}}         ........(1)

We are given:

P_{PCl_5}=217.0torr

P_{PCl_3}=13.2torr

P_{Cl_2}=13.2torr

Putting values in above equation, we get:

K_p=\frac{217.0}{13.2\times 13.2}\\\\K_p=1.24

Now we have to calculate the new partial pressure of Cl_2.

P_{PCl_5}+P_{PCl_3}+P_{Cl_2}=P_{Total}

217.0torr+13.2torr+P_{Cl_2}=263.0torr

P_{Cl_2}=32.8torr

The reaction is re-established and proceed to right direction by Le-Chatelier's principle to cancel the effect of addition of Cl_2.

Now, the equilibrium is shifting to the reactant side. The equation follows:

                       PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initial:             13.2         32.8            217.0

At eqm:         13.2-x      32.8-x         217.0+x

Putting values in expression 1, we get:

1.24=\frac{(217.0+x)}{(13.2-x)(32.8-x)}\\\\x=40.4,6.38

Neglecting the 40.4 value of 'x'  because pressure can not be more than initial partial pressure.

Thus, the value of 'x' will be, 6.38 torr.

Now we have to calculate the new partial pressures after equilibrium is reestablished.

Partial pressure of PCl_5 = (217.0+x) = (217.0+6.38) = 223.4 torr

Partial pressure of PCl_3 = (13.2-x) = (13.2-6.38) = 6.82 torr

Partial pressure of Cl_2 = (32.8-x) = (32.8-6.38) = 26.4 torr

Hence, the new partial pressures of PCl_5,PCl_3\text{ and }Cl_2 when equilibrium is re-established are 223.4 torr, 6.82 torr and 26.4 torr respectively.

7 0
3 years ago
Help PLEASEEEE EXTRA POINTS
AysviL [449]

C: Z because it is the only area of land that is darkened.

7 0
3 years ago
The initial pressure of a mixture of C6H6 and an excess of H2 in a rigid vessel is 1.21 atm. A catalyst is introduced. After the
KengaRu [80]

Answer:

mole fraction of C6H6 = 0.613 atm

Explanation:

The equation for this reaction is :

          C_6H_6 _{(g)} + 3H_2_{(g)} \to C_6H_{12}_{(g)}

Initial      P₁            P₂             0

Final        0           P₂ -P₁/2      P₁

After completion of the reaction;

P₁  +  P₂  = 1.21 atm                    ----- (1)

P₂  -  P₁/2 +  P₁ = 0.839 atm

P₂ + P₁/2 = 0.839 atm          ----- (2)

Subtracting (2) from (1); we have:

P₁/2 = 0.371

P₁ = 0.742 atm

From(1)

P₁  +  P₂  = 1.21 atm

0.742 atm + P₂  = 1.21 atm

P₂  = 1.21 atm - 0.742 atm

P₂  = 0.468 atm

Thus, the partial pressure of C6H6 = 0.742 atm

∴

Partial pressure = Total pressure × mole fraction of C6H6

mole fraction of C6H6 = Partial pressure /  Total pressure

mole fraction of C6H6 = 0.742 atm / 1.21 atm

mole fraction of C6H6 = 0.613 atm

5 0
3 years ago
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