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2 years ago

Write a balanced equation of decomposition reaction which is carried out by the catalyst

Chemistry

1 answer:

xz_007 [3.2K]2 years ago

3 0

Answer:

A decomposition reaction is a reaction in which the compound is broken up into its constituents.

A decomposition reaction is a reaction in which the compound is broken up into its constituents. When the decomposition is brought about by a catalyst, it is called catalytic decomposition.

Let us look at the catalytic decomposition of the compound potassium trioxochlorate V. in the presence of the catalysts manganese dioxide. The reaction occurs as follows;

2KClO3 -----> 2KCl + 3O2

Explanation:

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Describe the properties of oobleck when it behaves like a solid and a liquid.

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3 years ago

How to balance lead and silver acetate yields lead (||) acetate and silver

arsen [322]

The given elements put into an equation using their symbols are as follows:
Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2

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3 years ago

Can anyone do balance equation?

miss Akunina [59]

47)1-6 and 5&6-8 hope this helps!

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3 years ago

Will give branliest

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3 years ago

46.6 grams of mercury II sulfate (HgSO4) reacts with an excess of sodium Chloride (NaCl). How many grams of mercury II chloride

slega [8]

Answer:

$m_{HgCl_2}=42.7gHgCl_2$

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4$

In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:

$m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2$

Best regards.

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3 years ago