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3 years ago

When an object starts moving on its own,potential energy becomes kinetic energy.?

1 answer:

7 0

Yes because an object has kinetic energy when its moving only, and has only potential energy when velocity is zero and there is height but for your statement to be true,the object has to have some height so there can be potential which can become kinetic energy

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Reading the temperature of a solution by using a thermometer is an example of a(n) ________.

weeeeeb [17]

Answer:

i guess its example of observation

6 0

3 years ago

Please help with this question

tamaranim1 [39]

1.806x10^24
Written equation form(always start the equation off with what you know based off of the question!):

3mol(CCl4)•6.022x10^23/1mol = 1.806x10^24

Good luck!

3 0

3 years ago

For the following reaction,

jeka94

Answer:

The answer to your question is:

1.- CO

2.- 0.414 moles of CO2

Explanation:

Data

2CO + O2 ⇒ 2CO2

CO = 0.414 moles

O2 = 0.418

Process

theoretical ratio CO/O2 = 2/1 = 1

experimental ratio CO/O2 = 0.414/0.418 = 0.99

Then the limiting reactant is CO

2.-

2 moles of CO --------------- 2 moles of CO2

0.414 moles of CO --------- x

x = (0.414 x 2) / 2

x = 0.414 moles of CO2

5 0

3 years ago

What is the mass of 3.77mol of K3N?

AleksAgata [21]

<h3>Answer:</h3>

495 g K₃N

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.77 mol K₃N

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of K₃N - 3(39.10) + 14.01 = 131.31 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 3.77 \ mol \ K_3N(\frac{131.31 \ g \ K_3N}{1 \ mol \ K_3N})$
Multiply/Divide: $\displaystyle 495.039 \ g \ K_3N$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

495.039 g K₃N ≈ 495 g K₃N

5 0

3 years ago

Round each number to four significant figures

ira [324]

Answer:

84,791 » 8479

256.75 » 256.8

431,801 » 4318

0.00078100 » 0.0007810

Explanation:

$.$

5 0

3 years ago