Calculate the number of oxygen atoms in 2.00 moles of Mn2O7
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Answer:
6 stages
Explanation:
Given:
Copper ore contains:
4.3 wt% water
10.3 wt% CuSO₄
85.3 wt% rock
Feed rate = 11.7 tons per hour
solution produced is to be 10 wt% copper sulfate
90 wt% water
Now,
The CuSO₄ supplied through the feed = 10.3 wt% CuSO₄ × Feed rate
= 0.103 × 11.7
= 1.2051 tons per hour
also,
At each stage 2 tons of solution is collected
therefore,
The CuSO₄ collected in each stage
= weight of solution × 10 wt% copper sulfate
= 2 tons per hour × 0.1
= 0.2 tons per hour
also,
98% of the CuSO₄ is to be recovered
thus,
the amount of CuSO₄ to be recovered
= 0.98 × CuSO₄ supplied through the feed
= 0.98 × 1.2051 tons per hour
= 1.180998
Therefore,
The number of stages required =
=
= 5.90499 ≈ 6 stages
The mass of chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.
The mass of chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.
The given parameters;
- <em>mass of the sodium chloride, = 14.5 g</em>
- <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>
<em />
In the reaction above, we can deduce the following;
molecular mass of 2Nacl = 2(58.44) = 116.88 g
molecular mass of 2NaF = 2(42) = 84 g
molecular mass of Cl2 = 71 g
The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 84 g of NaF
14.5 g of NaCl ------------------- ?
The mass of chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 71 g of Cl2
14.5 g of NaCl ------------------- ?
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