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Lilit [14]
4 years ago
9

Which type of NAC agent will be used during the posture assessment before allowing access to the VPN users?

Computers and Technology
1 answer:
algol134 years ago
3 0

Answer:

Dissolvable NAC agent.

Explanation:

Dissolvable NAC agent is a part of the NAC(Network Admission Control) agent. The main advantage of dissolvable NAC agent does not need any installation of the device. In the dissolvable NAC agent, the login process is started by downloading the part of the agent on the website during the run time. The Dissolvable NAC agent is used in the posture assessment before allowing access permission to the VPN users.

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Write a function called median, that takes as parameter a full, sorted array of doubles and returns the median of the list. For
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Answer:

Explanation:

public class Lab8

{

public static double median(double list[])

{

int size=list.length;

if(size%2!=0)

return list[size/2];

else

return(list[size/2-1]+list[size/2])/2.0;

}

public static boolean issorted(double list[])

{

for(int i=0;i<list.length-1;i++)

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if(list[i]>list[i+1])

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}

public static void findcommon(int a1[],int a2[],int common[])

{

int c=0;

for(int i=0;i<a1.length;i++)

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boolean isFilled=false;

for(int j=0;j<c;j++)

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if(a1[i]==common[j])

{

isFilled=true;

break;

}

}

if(isFilled)

{

for(int k=0;k<a2.length;k++)

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if(a1[i]==a2[i])

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common[c]=a1[i];

c++;

break;

}

}

}

}

while(c<common.length)

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common[c]=0;

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public static void rotateRight(int list[])

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int temp=list[list.length-1];

for(int i=list.length-1;i>0;i--)

{

list[i]=list[i-1];

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public static int count(int list[],int n)

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if(list[i]==n)

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int stretchedList[]=new int[list.length*2];

int k=0;

for(int i=0;i<list.length;i++)

{

int n=list[i];

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{

System.out.print("[");

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{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

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System.out.println("]");

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System.out.print("[");

for(int i=0;i<arr.length;i++)

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if(i!=arr.length-1)

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System.out.println("]");

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public static void main(String[] args)

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double list1[]={1.1,2.2,3.3,4.4,5.5,6.6};

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System.out.println("List1:");

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double list2[]={1.1,2.2,3.3,4.4,6.6,5.5};

boolean result=issorted(list2);

System.out.println("List2:");

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System.out.println("List2 is a sorted array.(T/F):"+ result);

int list3[]={3,8,5,6,5,8,9,2};

int list4[]={5,15,4,6,7,3,9,11,9,3,12,13,14,9,5,3,13};

int list5[]=null;

if(list3.length<=list4.length)

list5=new int[list3.length];

else

list5=new int[list4.length];

findcommon(list3,list4,list5);

System.out.println("\n List3:");

printIntArray(list3);

System.out.println("\n List4:");

printIntArray(list4);

System.out.println("\n Array with common value,List5:");

printIntArray(list5);

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System.out.println("\n the array after rotate right:");

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int n=count(list7,3);

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printIntArray(list8);

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printIntArray(list9);

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