Answer:
Currency
Explanation:
Since sales are in money, and currency shows money, Currency is our answer
Answer:
<style>
p {
background-color: rgb(255, 0, 0);
}
h1 {
background-color: rgb(0, 255, 0);
}
ol {
background-color: rgb(97,51,47);
}
</style>
Explanation:
Put this at the top of your code. It should target the paragraph tag, the header h1 tag, and the Ordered List (OL) tag individually and set their background colors respectively.
It's been a while since I've done CSS so you might have to tweak the syntax a bit, but it should look something like that.
Answer:
Redundant paths can be available without causing logical Layer 2 loops.
Explanation:
- Spanning Tree Protocol is used to allow redundancy in the Layer 2 switched networks without creating cycles/circles also called loops.
- These loops are called physical loops.
- When two parts of the switched network are connected via two or more Layer 2 switches this result in a loop.
- This affects the performance of the network as the result of broadcast packets flooding.
- STP puts one port of the switch to forward mode and the rest of the ports within the same part of the network to the blocking mode to avoid broadcast packet flooding. STP puts all the ports that are allowing redundant paths to block mode and the one port that is left after this is placed in forward mode.
- Spanning Tree Algorithm is used by STP to determine the optimal path of switch to the network.
- Bridge Protocol Data Units are used to share the information about the optimal path determined by the spanning tree algorithm with other switches.
- This information helps STP to eliminate the redundant paths.
- So this is how STP tracks all the links in the switched network and eliminates redundant loops by allowing only one active path to the destination while blocking all other paths.
Answer:
#include <iostream>
using namespace std;
int main()
{
char fullname[30];
string fname="",lname="";
int i,j;
cout<<"Enter fullname\n";
cin.getline(fullname,30); //so that blank can be read
for(i=0;fullname[i]!=' ';i++)
fname+=fullname[i]; //fistname will be saved
cout<<"\n";
for(j=i;fullname[j]!='\0';j++)
lname+=fullname[j]; //lastname will be saved
cout<<"\nFirstname : "<<fname<<"\nLastname : "<<lname;
return 0;
}
OUTPUT :
Enter fullname
John thomson
Firstname : John
Lastname : thomson
Explanation:
cin.getline() should be used instead of cin in case of strings so that space can be read otherwise after blank string will be ignored.
Answer:
Hash condition is the correct answer to the following question.
Explanation:
Hash condition provided more security than the applocker file path rule and it is manually for the files.
- It is more secure than the path rule because each file has its separated hash condition.
- Drawback of hash file is every time whenever when file is updated then we have to update the file hash condition.
