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d1i1m1o1n [39]
2 years ago
12

The ratio of taxes to profits is 7:3. Find the amount of taxes if the taxes and profits total $1000.

Mathematics
1 answer:
Masteriza [31]2 years ago
4 0

Answer:

$700

Step-by-step explanation:

Given:

The ratio of taxes to profits is 7:3.

The taxes and profits total $1000.

Question asked:

Amount of taxes = ?

Solution:

Let ratios = x

And amount of taxes = 7x

Then amount of profit = 3x

Sum of amount of taxes and profits = $1000.(given)

                                                           = 7x + 3x = 1000\\= 10x = 1000\\

by dividing both side by 10

                                                         x = 100

Thus, amount of taxes = 7x = 7\times100 = 700

Thus, amount of profits = 3x = 3\times100 = 300

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A coffee shop uses two different-sized bins to store coffee beans. The volume of the smaller bin is r cubic inches and the volum
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r+y×(S×L)

Step-by-step explanation:

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3 years ago
The graph of a linear equation passes through three of these points: (0, 5), (2, 2), (3, 1), and (4, -1). The point that the gra
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(3,1) is the answer your looking for.

Step-by-step explanation:

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3 years ago
The populations of termites and spiders in a certain house are growing exponentially. The house contains 120 termites the day yo
zysi [14]

Answer:

in order to triple the inicial population of spiders, will take 50395 days

Step-by-step explanation:

we can define the termite population function as T(t) and the one for spiders as S(t) , where t represents time measured in days

since both have and exponencial growth

T(t)= a*e^(b*t)

S(t)= c*e^(d*t)

1) when the day the person moves in , t=0 and T(0)= 120 termites

T(0) = a*e^(b*0) = a = 120

2) after 4 days , t=4 and  the house contains T(4) = 210 termites

T(4)= 120*e^(b*4) = 210 → 4*b = ln (210/120) → b = (1/4)* ln(210/120)= 0.14

therefore

T(t) = 120*e^(0.14*t)

3) 3 days after moving in , t=3, there were T(3) = 120*e^(0.14*3)=182.63≈ 182 termites . The number of spiders is half of the number of termites → S(3) = T(3) * 1 spider/ 2 termites  =91.31 spiders ≈ 91 spiders

4) after 8 days of moving in , t=8, there were T(8) = 120*e^(0.14*8)=367.78≈ 368 termites . The number of spiders is 0.25 times the number of termites → S(8) = T(8) * 1 spider/ 4 termites =91.94 spiders   ≈ 92 spiders

from

S(t)= c*e^(d*t) → d = ln [S (tb)/S (ta) ] / (tb-ta)

therefore d = ln [ S(8)/S(3) ] / (8 - 3 ) = 2.18*10^-5

in order to triple the initial population

S(t3) = 3 *S(0) = 3*[c*e^(d*0)] = 3*c

S(t3) = c*e^(d*t3) = 3* c → t3 = ln(3) / d = 50395 days

5 0
3 years ago
Find the value of y.<br><br> A. 25.5<br> B. 18<br> C. 75<br> D. 36
Paladinen [302]

Answer: 18

Step-by-step explanation: Angles opposite of each other in a trapezoid equal 180 minus each other so 180 - 105 = 75 so 75 = 4y + 3

Subtract 3 from both sides

72 = 4y

Divide by 4

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8 0
2 years ago
Seriously need help with this question or I will fail my senior year
nlexa [21]

Answer:

you cheater

Step-by-step explanation:

Tring to cheat because you don't feel like doing it. Hopefully you fail so you can learn your lesson

5 0
2 years ago
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