Answer:
Step-by-step explanation:
They are also similar.
Both have 4 right angles. Both have 2 sets of parallel lines. Both have 4 equal sides.
But I think you are supposed to answer if figure 1 is similar to figure 2 and figure two is similar to figure 3 then by the transitive property, figure 1 is similar to figure 3.
K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE
g is taken as 9.81
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
Answer:
no because 2/3 is greater
Answer:
333.15 Kelvin (K)
Step-by-step explanation:
When you convert from Celsius to Kelvin, you add 273.15
60 C + 273.15 = 333.15 K
So, that is the answer. Hope this helps!
