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3 years ago

What are four numbers that fall between 9.18 9.19

Mathematics

1 answer:

bearhunter [10]3 years ago

5 0

For this question you would have to expand the numbers to the thounsandths
so it can be 9.181, 9.182, 9.183 and so on

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Simply: 200+(20-4)-2×3

alexandr1967 [171]

Answer:

The answer is 210

Step-by-step explanation:

200+(20-4)-2x3

first you'd do 20-4= 16

then you'd do 2x3=6

next you'd 16-6=10

finally 200+10=210

5 0

3 years ago

One of the great mysteries of the world is my hotdogs and hotdog buns come in packages of different sizes hotdogs come in packs

V125BC [204]

Answer:

3 pack of hot dogs and 2 pack of buns 24

Step-by-step explanation:

hot dogs come in packs of 8

burns came in packs of 12

what is the least number of each you can buy in order to have a equal number of hot dogs and buns

so to get equal number

we have to look for the LCM of 8 and 12 = 24

therefore the packs will be equal to product

hot dogs come in packs of 8 = 8*3 = 24

burns came in packs of 12 = 12 *2 = 24

therefore, 3 pack of hot dogs and 2 pack of buns 24

7 0

3 years ago

Who wants to play rocket league with me<br><br>I'm gold3 so sry

maw [93]

Answer:

Bet

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

X^4+64 will be the perfect square by adding<br><br>

lions [1.4K]

Answer:

$( { {x}^{2} })^{2} + 16 {x}^{2} + {8}^{2} \\ ( {x}^{2} + 8) ^{2} \\ ( { {x}^{2} })^{2} - 16 {x}^{2} + {8}^{2} \\ ( {x}^{2} - 8) ^{2}$

<h3><em>+16x² or -16x² is the answer</em></h3>

7 0

3 years ago

Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis

Licemer1 [7]

Answer:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

Step-by-step explanation:

For this case we have the following density function:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

7 0

3 years ago