Answer:the probability that a pensioner catches a flu is 0.3 or 
Step-by-step explanation:
<u>Data:</u>
a) Pensioners who have had a flu jab = 
b) Pensioners who did not had a flu jab = 1 -
= 
For the first pair of arrows: a is the probability of the upper arrow and b is the probability of the lower arrow.
<em>If pensioner have had a flu jab, the probability of catching flu is
</em>
Data:
c) Catching flu = 
d) Not catching flu = 1 -
= 
The second pair of arrows on the top: Top arrow is c and bottom arrow is d
<em>If pensioner did not have a flu jab, the probability of catching flu is
</em>
<u>Data:</u>
e) Catching flu = 
f) Not catching flu = 1 -
= 
The second pair of arrows on the bottom: Top arrow is e and bottom arrow is f.
Q) Probability pensioner catches a flu
P(catches the flu given that he had the flu jab) + P(catches the flu given that he did not have the flu jab)
(
x
) + (
x
)
= 0.02 + 0.28
= 0.3
Therefore, the probability that a pensioner catches a flu is 0.3 or 
Keyword: Probability
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-5/8 divided by -3/4 is the same as -5/8 multiplied by -4/3. Multiply the tops to get 20. Multiply the bottoms to get 24. A negative over a negative is positive and you end up with 20/24! :)
Answer:
a = 102.05
b = 393.76
B = 93°
Step-by-step explanation:
The law of sines tells you ...
a/sin(A) = b/sin(B) = c/sin(C)
Since the sum of angles in a triangle is 180°, angle B must be ...
B = 180° -72° -15° = 93°
and the unknown sides must be ...
a = c/sin(C)·sin(A) = 375·sin(15°)/sin(72°) ≈ 102.05192
B = 93°
b = 375·sin(93°)/sin(72°) ≈ 393.75796
_____
The rounding requirement got cut out of your picture, so we can't help you with that.
Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
Divide equation 1 by -17:{x+0 y = 4 | (equation 1)0 x+y = 1 | (equation 2)
Collect results:Answer: {x = 4 {y = 1
Please note the { are supposed to span over both equations but it interfaces doesn't allow it. Please see attachment for clarification.