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Bingel [31]
2 years ago
7

Find the equation of a line that passes through the point (2,-5) and is perpendicular to the y-axis. Do not put any spaces in yo

ur answer.
Mathematics
1 answer:
Allushta [10]2 years ago
3 0

Answer:

<em>y=-5</em>

Step-by-step explanation:

<u>Equation of the line</u>

Lines can be expressed in several forms. The slope-intercept form of the line is:

y = mx + b

Where m is the slope of the line and m is the y-intercept.

If the line is perpendicular to the y-axis, then it's a horizontal line. Horizontal lines have slope m=0, thus, the equation is:

y = b

To find the value of b, just substitute the given point:

-5=b

The equation of the line is:

y=-5

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lilavasa [31]

Answer:

Given the function: y=f(x) = 3x+2

when x=-2 at the beginning of the interval [-2, 5],

then;

y = 3x+2 begins at

y= 3(-2)+2 = -6+2= -4.

and

when x=5 at the end of the interval [-2, 5],

y = 3x+2 ends up at

y= 3(5)+2 = 15+2= 17.

So,

y has changed -4 to 17, which is a change of 17-(-4)= 17+4 = 21

and x has changed from -2 to 5, which is a change of 5-(-2)=5+2=7

So, the average rate of change of y with respect to x over the interval

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=

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Step-by-step explanation:

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3 years ago
Pleassdee need help I'll brainlist ​
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Answer:

A^2 means a*a

Step-by-step explanation:

A^2 = 5^2=5*5=25

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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7 0
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