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Bingel [31]
3 years ago
7

Find the equation of a line that passes through the point (2,-5) and is perpendicular to the y-axis. Do not put any spaces in yo

ur answer.
Mathematics
1 answer:
Allushta [10]3 years ago
3 0

Answer:

<em>y=-5</em>

Step-by-step explanation:

<u>Equation of the line</u>

Lines can be expressed in several forms. The slope-intercept form of the line is:

y = mx + b

Where m is the slope of the line and m is the y-intercept.

If the line is perpendicular to the y-axis, then it's a horizontal line. Horizontal lines have slope m=0, thus, the equation is:

y = b

To find the value of b, just substitute the given point:

-5=b

The equation of the line is:

y=-5

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The equations 4x + 2y = 4 and – x2 + y = –6 intersect at the coordinates (a,
soldier1979 [14.2K]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
Please help! i’ll give you a coookie!!
olga2289 [7]

Answer:

60 m

Step-by-step explanation:

since the triangles are similar, you can find the missing length d using the equation 140/105 = 80/d, then simplify

4 0
3 years ago
If f(x)=4x-1 and g(x)=x^2+7 ,find G(f(x))
algol13

Answer:

16x² - 8x + 8

Step-by-step explanation:

f(x)=4x-1

g(x)=x²+7

g(f(x)) = g(4x-1) = (4x - 1)² + 7 = 16x² - 2*4x*1 +1² + 7= 16x² - 8x + 8

4 0
3 years ago
Find a. Round to the nearest tenth:
Ulleksa [173]

Step-by-step explanation:

In the following triangle, a= ? , b= 2cm.

m<B= 105° , m<C = 15° ,m< A =?

Now, we know that sum of the interior angles of the triangle = 180°

m<B+m<C +m< A =180°

105°+15°+m< A=180°

m< A= 180- 120° = 60°

\frac{ \sin( A) }{a}  =  \frac{ \sin(B) }{b}

\frac{ \sin(60) }{a}  =  \frac{ \sin(105) }{2}

a =  \frac{ \sin(60) }{ \sin(105) }  \times 2

a = 1.79

a = 1.8

6 0
3 years ago
Help me please I been trying to figure out how to do this problem
Marina86 [1]

sin 30 = x/4

sin 30 = 0.5

0.5 = x/4

x = 2

5 0
2 years ago
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