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Alexeev081 [22]
3 years ago
14

The last option 0.353 pounds per cubic foot

Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

Step-by-step explanation:

something

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Use distributive law to factor the given expression: 3+21a+15b
Reil [10]

Answer:

3(1+7a+5b)

Step-by-step explanation:

The distributive law states that

a\cdot (b+c)=a\cdot b+a\cdot c.

The expression 3+21a+15b consists of three terms:

  1. 3=3·1;
  2. 21a=3·7a;
  3. 15b=3·5b.

You can see that 3 is the common factor of these three terms, thus

3+21a+15b=3(1+7a+5b).

6 0
3 years ago
Combine the like terms to create an equivalent expression:<br>-5r+8r+5​
Olegator [25]
Answer : 3r+5 hope this helps!
3 0
3 years ago
Can anyone help me with this dont answer if you dont no what it is and no deleting answers
Mkey [24]
The answer to this question is the second choice, jessica bought 1/4 more than derek

6 0
2 years ago
Calculate the value of the exterior angle
aev [14]

What we know is that the sum of a triangle's internal angles are 180º, and a straight angle makes 180º.

first, we have to find the third internal angle(let's call it n) so that we can use it to find the exterior angle.

(3x + 20) + (4x + 5) + n = 180

simplify:

7x + 25 + n = 180

7x + n = 155

n = 155 - 7x

Now we can add it to the external angle to find x.

(155 - 7x) + (8x + 15) = 180

simplify:

170 + 8x - 7x = 180

170 + x = 180

x = 10

Now we can substitute it to the external angle.

8 x 10 + 15 = 95

the exterior angle is 95º.

8 0
3 years ago
Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

4 0
1 year ago
Read 2 more answers
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