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V125BC [204]
3 years ago
14

I NEED HELP PLEASE, THANKS! :)

Physics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Answer:

In terms of object produced, it means that the magnification decreases. Since it is negative, it means that the image produced is smaller than the actual object. Since, it is also the ratio of height of the object to the height of the image, It also means that the height of object is smaller than the height of image.

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(0 10 40 20 30 50 70 80) (90 100 110 120 130 140). Which end of the scale (left or right) has the loudest sounds?​
gregori [183]
I think 140 would be the loudest.
8 0
2 years ago
(1 point) A mass m=4kg is attached to both a spring with spring constant k=577N/m and a dash-pot with damping constant c=4N⋅s/m
sasho [114]

Answer:

The function is x = e^(-t/2) * (0.792*sin12t + 5cos12t)

Explanation:

we have to:

m = mass = 4 kg

k = spring constant = 577 N/m

c = damping constant = 4 N*s/m

The differential equation of motion is equal to:

m(d^2x/dt^2) + c(dx/dt) + k*x = 0

Replacing values:

4(d^2x/dt^2) + 4(dx/dt) + 577*x = 0

Thus, we have:

4*x^2 + 4*x + 577 = 0

we will use the quadratic equation to solve the expression:

x = (-4 ± (4^2 - (4*4*577))^1/2)/(2*4) = (-4 ± (-9216))/8 = (1/2)  ± 12i

The solution is equal to:

x = e^(1/2) * (c1*sin12t + c2*cos12t)

x´ = (-1/2)*e^(1/2) * (c1*sin12t + c2*cos12t) + e^(-t/2) * (12*c1*cos12t - 12*c2*sin12t)

We have the follow:

x(0) = 5

e^0(0*c1 + c2) = 5

c2 = 5

x´(0) = 7

(-1/2)*e^0 * (0*c1 + c2) + e^0 * (12*c1 - 0*c2) = 7

(-1/2)*(5) + 12*c1 = 7

Clearing c1:

c1 = 0.792

The function is equal to:

x = e^(-t/2) * (0.792*sin12t + 5cos12t)

8 0
3 years ago
A horizontal spring with spring constant 750 N/m is attached to a wall. An athlete presses against the free end of the spring, c
ANTONII [103]

Answer:

37.5 N Hard

Explanation:

Hook's law: The force applied to an elastic material is directly proportional to the extension provided the elastic limit of the material is not exceeded.

Using the expression for hook's law,

F = ke.............. Equation 1

F = Force of the athlete, k = force constant of the spring, e = extension/compression of the spring.

Given: k = 750 N/m, e = 5.0 cm = 0.05 m

Substitute into equation 1

F = 750(0.05)

F = 37.5 N

Hence the athlete is pushing 37.5 N hard

4 0
3 years ago
Read 2 more answers
Find the equilibrant of two 10.0-N forces acting upon a body when the angle between the forces is 90° Solve graphically using a
bazaltina [42]

The equilibrant force of the two given forces is 14.14 N.

<h3 /><h3 /><h3>What is equilibrant force?</h3>
  • This is a single force that balances other given forces.

The given parameters:

  • First force, F₁ = 10 N
  • Second force, F₂ = 10 N
  • Angle between the forces, θ = 90⁰

The equilibrant force of the two given forces is calculated as follows;

F = \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{(10)^2 + (10)^2} \\\\F = 14.14 \ N

Thus, the equilibrant force of the two given forces is 14.14 N.

Learn more about equilibrant force here: brainly.com/question/8045102

5 0
3 years ago
Nitromethane (ch3no2) burns in air to produce significant amounts of heat. 2 ch3no2(l) + 3 2 o2( g) ¡ 2 co2( g) + 3 h2o(l) + n2
ANEK [815]

From the balanced reaction, we are given that 1418 kJ of heat is released for every 2 moles of nitromethane (CH3NO2) reacted.

So first calculate the moles of CH3NO2:

moles CH3NO2 = 5560 g / (61.04 g/mol)

moles CH3NO2 = 91.1 mol

 

So total heat released is:

total heat = (-1418 kJ / 2mol) * 91.1 mol

<span>total heat = -129,162.52 kJ = -129.16 MJ</span>

6 0
3 years ago
Read 2 more answers
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